Bohr model of Vanadium Atom-How to draw Vanadium (V) Bohr-Rutherford diagram?

Bohr model describes the visual representation of orbiting electrons around the small nucleus. It used different electron shells such as K, L, M, N…so on. These shells hold a specific number of electrons, the electron shell which is closest to the nucleus has less energy and the electron shell which is farthest from the nucleus has more energy.

Bohr diagram is very interesting and easy to draw. Here, we will draw the Bohr diagram of the Vanadium atom with some simple steps.

Steps to draw the Bohr Model of Vanadium atom

1. Find the number of protons, electrons, and neutrons in the Vanadium

Protons are the positively charged particles and neutrons are the uncharged particles, both these are constituents of the atom nuclei. Electrons are the negatively charged particles that orbit the nucleus of an atom

To find the number of protons an atom contains, just look at its atomic number.

If the atomic number of atom is 45, then proton will also be 45, if atomic number is 46, then proton will also be 46.

So, the atomic number for Vanadium is 23, hence, the number of protons in the Vanadium atom is also 23.

Now, to determine the number of neutrons in an atom, use this formula.

⇒ Number of neutrons in atom = Atomic mass of the atom(rounded to the nearest whole number) – Number of proton in an atom

For example, An atom have 33.988 atomic mass and 16 protons.

Then, to find the number of neutron, round the atomic mass to the near whole number, so, atomic mass 33.988 round to 34.

= (34 – 16 protons) = 18 number of neutrons in the atom

Now, To get the number of neutrons in a Vanadium atom, look at its atomic mass which is 50.94 rounded to 51, and the number of protons in Vanadium is 23.

∴ Hence, the number of neutrons in Vanadium atom = (51 – 23) = 28

It should be noted that “The number of electrons in a neutral atom is equal to the number of protons”.

So, the Vanadium atom is neutral, hence, its number of electrons will be equal to the number of protons which is 23 as we already discussed.

⇒ The number of electrons in a Vanadium atom = 23

⇒ The number of protons in a Vanadium atom = 23

⇒ The number of neutrons in a Vanadium atom = 28

Let’s read in detail – How to find number of protons, electrons, neutrons?

2. Draw the nucleus of an atom

A nucleus is a dense and small region that contains the number of protons and neutrons of an atom.

In this step, we have to draw a small circle that consists of a number of protons and the number of neutrons of a Vanadium atom.

3. Draw the First electron shell

“An electron shell may be thought of as an orbit followed by electrons around an atom’s nucleus.”

The first electron shell is also called the K-shell, this is the closest shell to the nucleus of an atom and can hold a maximum of two electrons.

As we know, the Vanadium atom has a total of 23 electrons. So, put two electrons from it, in the first shell, next to each other.

We have successfully drawn the first shell of the Vanadium atom that can hold 2 electrons. As a Vanadium atom has a total of 23 electrons, and from 23 electrons we have used two electrons in the first shell.

∴ (23 – 2) = 21 electrons 

Therefore, we are left with 21 electrons, let’s put them in the next shells of the Vanadium atom.

4. Draw the Second electron shell

The second shell also called the L-shell that can hold a maximum of 8 electrons. This shell is drawn after the first electron shell.

In the second electron shell, the electrons are added one at a time, starting from the top position and then going in a clockwise direction.

In second shell, electrons are added one at a time in clockwise direction as a clock position – 12 o’clock, 3 o’clock, 6 o’clock, 9 o’clock positions.

Once you place the electrons one at a time to each of the four sides(Top – Right – Bottom – Left], start pairing or doubling them.

So, we have 21 remaining electrons of a Vanadium atom, and the 2nd shell can only hold a maximum of 8 electrons.

Therefore, put the 8 electrons of the Vanadium atom in the 2nd electron shell, start from the top position, put electrons one at a time, and go in a clockwise direction(Top – Right – Bottom – Left). And, finally, pair them up.

At this step, out of the 23 electrons of the Vanadium atom, we have placed 2 electrons in the first shell and 8 electrons in the second shell.

∴ [23 – (2+8)] = 13 electrons.

This means we are now left with 13 electrons. So let’s see how we can assign them their appropriate positions in the next shells of the Vanadium atom.

5. Draw the Third electron shell

The third electron shell also called the M-shell can accommodate up to 18 electrons. For the elements in the first few periods of the Periodic Table, the third shell holds up to 8 electrons only. But actually, in totality, it has the capacity to hold 18 electrons.

⇒ The third subshell exhibits this capacity of holding ‘up to 18’’ electrons for atomic numbers greater than 20 such as 21, 22, 23, 24 and so on.

⇒ This 18 electron-holding property of the third shell is specifically important for the d-block elements (Scandium to Zinc).

⇒ The M-shell is divided into subshells (s, p, and d). s can hold only 2 electrons. 6 electrons can be placed in the p-subshell. 2+6 =8, so after these 8 electrons, the rest of the electrons can be placed in the d-subshell of the third shell.

So, it is due to the presence of the d-subshell that the third shell can hold more than 8 and up to 18 electrons in total.

⇒ Another rule to keep in mind is that the filling of electrons follows the Aufbau Principle. Electrons are filled diagonally.

After completely filling the s and p subshell of shell number 3, 2 electrons are accommodated in the s-subshell of the fourth shell. Only then the remaining electrons are placed in the 3d subshell of the third shell.

Let’s see how that’s done.

Out of the 13 electrons left of the Vanadium atom, we place 8 electrons in the third shell, moving in a clockwise manner as we have done for electrons in step 4.

∴ 13 – 8 = 5.

As we already told you, after the 8 electrons in the third shell, we first need to place 2 electrons in the fourth shell and then come back to place the remaining electrons into the third shell again.

Thus, let us place 2 electrons out of the 5 left in the fourth shell first.

6. Draw the Fourth electron shell

Here, we draw the fourth electron shell and put 2 electrons in it. Starting from the top position, put the electrons one at a time while moving in a clockwise direction (Top-Right—Bottom-Left). Here we have only 2 electrons to put in the fourth shell, so one is placed at the top while the other is situated at the right end as shown below.

∴ 5 – 2 = 3.

We are left with 3 electrons so now we will go back and place these 3 electrons into the third shell, again in a clockwise manner.

7. Place the remaining electrons back into the Third electron shell

The remaining 3 electrons of Vanadium are placed into the Third electron shell, as shown below.

Now, the 3rd shell has a total of 11 electrons.

The third electron shell keeps on filling in the same manner in the first-row transition metals (Sc to Zn) till this shell is filled to its maximum capacity of holding 18 electrons. But we are not concerned with that in this article.

So for now, you have the Bohr model of the Vanadium atom that contains 23 protons and 28 neutrons in the nucleus region while a total of 23 electrons circulate around the nucleus in specific orbits called shells.

The first electron shell of Vanadium has 2 electrons, there are 8 electrons in the second shell, 11 electrons in the third shell, and 2 electrons are present in the fourth shell of the Vanadium atom.

Also Read:-

• Scandium Bohr model
• Titanium Bohr model
• Oxygen Bohr model
• Boron Bohr model
• Beryllium Bohr model
• Lithium Bohr model
• Helium Bohr model
• Nitrogen Bohr model
• Fluorine Bohr model
• Neon Bohr model
• Carbon Bohr model
• Sodium Bohr model
• Silicon Bohr model
• Magnesium Bohr model
• Sulfur Bohr model
• Chlorine Bohr model
• Phosphorus Bohr model
• Aluminum Bohr model
• Argon Bohr model
• Potassium Bohr model
• Bromine Bohr model
• Calcium Bohr model
• Silver Bohr model
• Arsenic Bohr model
• Gold Bohr model
• Krypton Bohr model
• Iodine Bohr model
• Copper Bohr model
• Iron Bohr model
• Uranium Bohr model
• Nickel Bohr model

Also check :- Bohr model for all elements of Periodic table

Find the Valence electron of Vanadium through its Bohr diagram

From the Bohr diagram of an atom, we can easily find the number of valence electrons in an atom by looking at its outermost shell.

Now to determine the valence electrons present in the Vanadium atom, have a quick look at its Bohr diagram.

The Bohr diagram of Vanadium has four electron shells (K, L, M, N), the K-shell is the innermost shell while the outermost shell is the N-shell.

Generally, the outermost shell of an atom is also called the valence shell. According to that, definition, the electrons present in the N-shell of the Vanadium atom are its valence electrons.

The outermost shell i.e., N-shell in the Vanadium Bohr model contains 2 electrons hence the number of valence electrons present in the Vanadium atom should also be 2. 

An important point to remember is that valence electrons are also defined as the electrons of an atom that can participate in bond formation during a chemical reaction.

And the transition metal (d-block) elements such as Vanadium (V) are famous for their ability to use the electrons present in their 3d sub-shell in addition to the 4s electrons in chemical bonding.

Read more – Valence electrons of transitions metals

So, as there is 3 electrons present in the 3d subshell of V in addition to 2 electrons in its outermost shell hence Vanadium is actually believed to have a total of 3+2 = 5 valence electrons. But this concept is beyond the Bohr model.

Electron dot diagram of a Vanadium atom

The electron dot diagram also called Lewis’s structure of an atom represents the total valence electrons present in it.

As there are 5 valence electrons in an atom of Vanadium (V) so there are 5 dots around the Vanadium atom in its electron dot diagram, as shown below.

The electron configuration of Vanadium

Vanadium has an atomic number of 23 and it contains a total number of 23 electrons. From the Bohr model of Vanadium, we know that it has 2 electrons in the K-shell, 8 electrons in the L-shell, 11 electrons in the M-shell, and 2 electrons in the N-shell.

So based on this electron distribution between the shells, the electronic configuration of the Vanadium atom is [2,8,11,2].

Or the electronic configuration of Vanadium is [Ar] 3d³ 4s² since it contains a total of 23 electrons.

Also Read:-

• Vanadium orbital diagram, electron configuration, and valence electrons
• How to write the electron configuration for any atom?

FAQ

Summary

• The Bohr model of Vanadium (V) is drawn with four electron shells, the first shell contains 2 electrons, the second shell contains 8 electrons, the third shell contains 11 electrons and the fourth shell contains 2 electrons.
• The atomic number of Vanadium is 23. As Vanadium (V) is a neutral atom hence the number of protons and electrons available for its Bohr diagram are equal i.e., 23.
• The number of neutrons for the Bohr diagram of Vanadium can be found by subtracting the number of protons from the atomic mass (rounded off to the nearest whole number).
• The electron configuration of Vanadium in terms of the shells is [2,8,11,2] while in the standard form it is [Ar] 3d³ 4s².