Bohr model of Titanium Atom-How to draw Titanium (Ti) Bohr-Rutherford diagram?
The Bohr Model of Titanium (Ti) has a nucleus that contains 26 neutrons and 22 protons. This nucleus is surrounded by four electron shells namely K-shell, L-shell, M-shell, and N-shell. The N-shell is the outermost shell in an atom of Titanium. The first shell has 2 electrons, 2nd shell has 8, 3rd shell has 10, and 4th shell has 2 electrons.
|Name||Titanium Bohr Model|
|Number of neutrons||26|
|Number of protons||22|
|Number of electrons||22|
|Total electron shells||4|
|Electron in the First shell(K)||2|
|Electrons in the Second shell(L)||8|
|Electrons in the Third shell(M)||10|
|Electrons in the Fourth shell(N)||2|
|Total valence electrons in Titanium||4|
How to draw Bohr Model of Titanium (Ti)?
Bohr model describes the visual representation of orbiting electrons around the small nucleus. It used different electron shells such as K, L, M, N…so on. These shells hold a specific number of electrons, the electron shell which is closest to the nucleus has less energy and the electron shell which is farthest from the nucleus has more energy.
Bohr diagram is very interesting and easy to draw. Here, we will draw the Bohr diagram of the Titanium atom with some simple steps.
Steps to draw the Bohr Model of Titanium atom
1. Find the number of protons, electrons, and neutrons in the Titanium
Protons are the positively charged particles and neutrons are the uncharged particles, both these are constituents of the atom nuclei. Electrons are the negatively charged particles that orbit the nucleus of an atom
To find the number of protons an atom contains, just look at its atomic number.
If the atomic number of atom is 45, then proton will also be 45, if atomic number is 46, then proton will also be 46.
So, the atomic number for Titanium is 22, hence, the number of protons in the Titanium atom is also 22.
Now, to determine the number of neutrons in an atom, use this formula.
⇒ Number of neutrons in atom = Atomic mass of the atom(rounded to the nearest whole number) – Number of proton in an atom
For example, An atom have 33.988 atomic mass and 16 protons.
Then, to find the number of neutron, round the atomic mass to the near whole number, so, atomic mass 33.988 round to 34.
= (34 – 16 protons) = 18 number of neutrons in the atom
Now, To get the number of neutrons in a Titanium atom, look at its atomic mass which is 47.86 rounded to 48, and the number of protons in Titanium is 22.
∴ Hence, the number of neutrons in Titanium atom = (48 – 22) = 26
It should be noted that “The number of electrons in a neutral atom is equal to the number of protons”.
So, the Titanium atom is neutral, hence, its number of electrons will be equal to the number of protons which is 22 as we already discussed.
⇒ The number of electrons in a Titanium atom = 22
⇒ The number of protons in a Titanium atom = 22
⇒ The number of neutrons in a Titanium atom = 26
Let’s read in detail – How to find number of protons, electrons, neutrons?
2. Draw the nucleus of an atom
A nucleus is a dense and small region that contains the number of protons and neutrons of an atom.
In this step, we have to draw a small circle that consists of a number of protons and the number of neutrons of a Titanium atom.
3. Draw the First electron shell
“An electron shell may be thought of as an orbit followed by electrons around an atom’s nucleus.”
The first electron shell is also called the K-shell, this is the closest shell to the nucleus of an atom and can hold a maximum of two electrons.
As we know, the Titanium atom has a total of 22 electrons. So, put two electrons from it, in the first shell, next to each other.
We have successfully drawn the first shell of the Titanium atom that can hold 2 electrons. As a Titanium atom has a total of 22 electrons, and from 22 electrons we have used two electrons in the first shell.
∴ (22 – 2) = 20 electrons
Therefore, we are left with 20 electrons, let’s put them in the next shells of the Titanium atom.
4. Draw the Second electron shell
The second shell also called the L-shell that can hold a maximum of 8 electrons. This shell is drawn after the first electron shell.
In the second electron shell, the electrons are added one at a time, starting from the top position and then going in a clockwise direction.
In second shell, electrons are added one at a time in clockwise direction as a clock position – 12 o’clock, 3 o’clock, 6 o’clock, 9 o’clock positions.
Once you place the electrons one at a time to each of the four sides(Top – Right – Bottom – Left], start pairing or doubling them.
So, we have 20 remaining electrons of a Titanium atom, and the 2nd shell can only hold a maximum of 8 electrons.
Therefore, put the 8 electrons of the Titanium atom in the 2nd electron shell, start from the top position, put electrons one at a time, and go in a clockwise direction(Top – Right – Bottom – Left). And, finally, pair them up.
As we have a total of 22 electrons for the Titanium atom and we placed 2 electrons in the first shell and 8 electrons in the second shell.
∴ [22 – (2+8)] = 12 electrons.
This means we are now left with 12 electrons. So let’s see how we can assign them their appropriate positions in the next shells of the Titanium atom.
Let’s place it in the next shells.
5. Draw the Third electron shell
The third electron shell also called the M-shell can accommodate up to 18 electrons. For the elements in the first few periods of the Periodic Table, the third shell holds up to 8 electrons only. But actually, in totality, it has the capacity to hold 18 electrons.
⇒ The third subshell exhibits this capacity of holding ‘up to 18’’ electrons for atomic numbers greater than 20 such as 21, 22, 23, 24 and so on.
⇒ This 18 electron-holding property of the third shell is specifically important for the d-block elements (Scandium to Zinc).
⇒ The M-shell is divided into subshells (s, p, and d). s can hold only 2 electrons. 6 electrons can be placed in the p-subshell. 2+6 =8, so after these 8 electrons, the rest of the electrons can be placed in the d-subshell of the third shell.
So, it is due to the presence of the d-subshell that the third shell can hold more than 8 and up to 18 electrons in total.
⇒ Another rule to keep in mind is that the filling of electrons follows the Aufbau Principle. Electrons are filled diagonally.
After completely filling the s and p subshell of shell number 3, 2 electrons are accommodated in the s-subshell of the fourth shell. Only then the remaining electrons are placed in the 3d subshell of the third shell.
Let’s see how that’s done.
Out of the 12 electrons left of the Titanium atom, we place 8 electrons in the third shell, moving in a clockwise manner as we have done for electrons in step 4.
∴ 12 – 8 = 4.
As we already told you, after the 8 electrons in the third shell, we first need to place 2 electrons in the fourth shell and then come back to place the remaining electrons into the third shell again.
Thus, let us place 2 electrons out of the 4 left in the fourth shell first.
6. Draw the Fourth electron shell
Here, we draw the fourth electron shell and put 2 electrons in it. Starting from the top position, put the electrons one at a time while moving in a clockwise direction (Top-Right—Bottom-Left). Here we have only 2 electrons to put in the fourth shell, so one is placed at the top while the other is situated at the right end as shown below.
∴ 4 – 2 = 2.
We are left with only 2 electrons so now we will go back and place these 2 electrons into the third shell.
7. Place the remaining electrons back into the Third electron shell
The remaining 2 electrons of Titanium is placed into the Third electron shell, as shown below.
Now, the 3rd shell has a total of 10 electrons.
The third electron shell keeps on filling in the same manner in the first-row transition metals (Sc to Zn) till this shell is filled to its maximum capacity of holding 18 electrons. But we are not concerned with that in this article.
So for now, you have the Bohr model of the Titanium atom that contains 22 protons and 26 neutrons in the nucleus region while a total of 22 electrons circulate around the nucleus in specific orbits called shells.
The first electron shell of Titanium has 2 electrons, there are 8 electrons in the second shell, 10 electrons in the third shell, and 2 electrons are present in the fourth shell of the Titanium atom.
- Scandium Bohr model
- Vanadium Bohr model
- Oxygen Bohr model
- Boron Bohr model
- Beryllium Bohr model
- Lithium Bohr model
- Helium Bohr model
- Nitrogen Bohr model
- Fluorine Bohr model
- Neon Bohr model
- Carbon Bohr model
- Sodium Bohr model
- Silicon Bohr model
- Magnesium Bohr model
- Sulfur Bohr model
- Chlorine Bohr model
- Phosphorus Bohr model
- Aluminum Bohr model
- Argon Bohr model
- Potassium Bohr model
- Bromine Bohr model
- Calcium Bohr model
- Silver Bohr model
- Arsenic Bohr model
- Gold Bohr model
- Krypton Bohr model
- Iodine Bohr model
- Copper Bohr model
- Iron Bohr model
- Uranium Bohr model
- Nickel Bohr model
Also check :- Bohr model for all elements of Periodic table
Find the Valence electron of Titanium through its Bohr diagram
From the Bohr diagram of an atom, we can easily find the number of valence electrons in an atom by looking at its outermost shell.
Now to determine the valence electrons present in the Titanium atom, have a quick look at its Bohr diagram.
The Bohr diagram of Titanium has four electron shells (K, L, M, N), the K-shell is the innermost shell while the outermost shell is the N-shell.
Generally, the outermost shell of an atom is also called the valence shell. According to that, definition, the electrons present in the N-shell of the Titanium atom are its valence electrons.
The outermost shell i.e., N-shell in the Titanium Bohr model contains 2 electrons hence the number of valence electrons present in the Titanium atom should also be 2.
An important point to remember is that valence electrons are also defined as the electrons of an atom that can participate in bond formation during a chemical reaction.
And the transition metal (d-block) elements such as Titanium (Ti) are famous for their ability to use the electrons present in their 3d sub-shell in addition to the 4s electrons in chemical bonding.
Read more – Valence electrons of transition metals
So, as there is 2 electrons present in the 3d subshell of Ti in addition to 2 electrons in its outermost shell hence Titanium is actually believed to have a total of 2+2 = 4 valence electrons. But this concept is beyond the Bohr model.
Electron dot diagram of a Titanium atom
The electron dot diagram also called Lewis’s structure of an atom represents the total valence electrons present in it.
As there are 4 valence electrons in an atom of Titanium (Ti) so there are 4 dots around the Titanium atom in its electron dot diagram, as shown below.
The electron configuration of Titanium
Titanium has an atomic number of 22 and it contains a total number of 22 electrons. From the Bohr model of Titanium, we know that it has 2 electrons in the K-shell, 8 electrons in the L-shell, 10 electrons in the M-shell, and 2 electrons in the N-shell.
So based on this electron distribution between the shells, the electronic configuration of the Titanium atom is [2,8,10,2].
Or the electronic configuration of Titanium is [Ar] 3d2 4s2 since it contains a total of 22 electrons.
- Titanium orbital diagram, electron configuration, and valence electrons
- How to write the electron configuration for any atom?
What is the Bohr diagram?
|Bohr model describes the visual representation of orbiting electrons around the small nucleus. It used different electron shells such as K, L, M, N…so on.|
How many electron shells a Titanium Bohr model contains?
Electron shells are also called energy levels. You can find the number of electron shells for an element by knowing its period number in the Periodic Table.
The elements or atoms in the first period of the Periodic Table have one energy level or one electron shell, same as the elements in the second period have two energy levels or two electron shells, and so on.
As the Titanium (Ti) atom belongs to the 4th Period in the periodic table, hence the number of electron shells for the Bohr model of Titanium is also 4. There are 4 electron shells in the Titanium Bohr model namely K-shell, L-shell, M-shell, and N-shell.
How many valence electrons are present in a Titanium atom Bohr diagram?
The outermost shell also called the valence shell is the shell that contains the valence electrons of an atom.
According to the Bohr diagram of Titanium, its outer shell is shell number 4 i.e., the N-shell containing 2 valence electrons. But the total number of valence electrons present in Ti is 4 because it can use its 3d electrons in addition to the 4s electrons during chemical bonding. Two 3d electrons and two 4s electrons make a total of 4 valence electrons in Ti.
- The Bohr model of Titanium (Ti) is drawn with four electron shells, the first shell contains 2 electrons, the second shell contains 8 electrons, the third shell contains 10 electrons and the fourth shell contains 2 electrons.
- The atomic number of Titanium is 22. As Titanium (Ti) is a neutral atom hence the number of protons and electrons available for its Bohr diagram are equal i.e., 22.
- The number of neutrons for the Bohr diagram of Titanium can be found by subtracting the number of protons from the atomic mass (rounded off to the nearest whole number).
- The electron configuration of Titanium in terms of the shells is [2,8,10,2] while in the standard form it is [Ar] 3d2 4s2.
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