The molar mass and molecular weight of Sucrose (C12H22O11) is 342.3007 g/mol.
The composition of the C12H22O11 formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Oxygen | O | 15.9994 g/mol | 11 | 175.9934 g/mol | 51.4148% |
| Hydrogen | H | 1.00797 g/mol | 22 | 22.1753 g/mol | 6.4783% |
| Carbon | C | 12.011 g/mol | 12 | 144.1320 g/mol | 42.1068% |
How to find the molar mass of Sucrose (C12H22O11)?
The molar mass and molecular weight of Sucrose (C12H22O11) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the C12H22O11 compound.
The given compound is C12H22O11. It comprises atoms from 3 different elements i.e., Oxygen (O), Hydrogen (H) and Carbon (C).
Step II: Find the atomic weight of each element in the C12H22O11.
Here is the list of atomic weights for all elements, let’s check the Oxygen (O), Hydrogen (H) and Carbon (C) atom’s atomic weight.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
Step III: Determine the number of atoms of each element present in the C12H22O11 compound.
As per the chemical formula, C12H22O11, It is made up of 11 Oxygen atoms, 22 Hydrogen atoms and 12 Carbon atoms.
| Element | Number of Atoms |
|---|---|
| O (Oxygen) | 11 |
| H (Hydrogen) | 22 |
| C (Carbon) | 12 |
Step IV: Calculate the molar mass of the Sucrose (C12H22O11) compound by applying the formula:
For Sucrose (C12H22O11):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of C12H22O11 = [(15.9994 x 11) + (1.00797 x 22) + (12.011 x 12)]
Molar mass of C12H22O11 = 175.9934 + 22.1753 + 144.132 = 342.3007 g/mol
Result: The molecular weight and molar mass of Sucrose (C12H22O11) is 342.3007 g/mol.
FAQs
What is the mass percent composition of Oxygen (O) in Sucrose (C12H22O11)? |
To find the mass percent of Oxygen in C12H22O11, follow the steps given below:
∴ Mass of Oxygen in C12H22O11 = 15.9994 x 11 = 175.9934 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in C12H22O11 = (Mass of Oxygen in C12H22O11/Molar mass of C12H22O11) × 100% Result: C12H22O11 contains 51.41 % of Oxygen as per its chemical composition.
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What is the mass percent composition of Hydrogen (H) in Sucrose (C12H22O11)? |
To find the mass percent of Hydrogen in C12H22O11, follow the steps given below:
∴ Mass of Hydrogen in C12H22O11 = 1.00797 x 22 = 22.1753 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in C12H22O11 = (Mass of Hydrogen in C12H22O11/Molar mass of C12H22O11) × 100% Result: C12H22O11 contains 6.48 % of Hydrogen as per its chemical composition.
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What is the mass percent composition of Carbon (C) in Sucrose (C12H22O11)? |
To find the mass percent of Carbon in C12H22O11, follow the steps given below:
∴ Mass of Carbon in C12H22O11 = 12.011 x 12 = 144.1320 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in C12H22O11 = (Mass of Carbon in C12H22O11/Molar mass of C12H22O11) × 100% Result: C12H22O11 contains 42.11 % of Carbon as per its chemical composition.
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What is the atomic percentage composition of elements in Sucrose (C12H22O11)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For C12H22O11: The atomic percentage composition of elements in the compound is: Atomic percentage of Oxygen (O) in C12H22O11: Atomic percentage of Hydrogen (H) in C12H22O11: Atomic percentage of Carbon (C) in C12H22O11:
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How many grams of Oxygen are present in 1 mole of C12H22O11? |
| There are 11 O-atoms in a C12H22O11 molecule. • Atomic weight of a O-atom = 15.9994 g/mol ∴ Total mass of Oxygen in 1 mole of C12H22O11 = 11 x 15.9994 = 175.99 g. Therefore there are 175.99 grams of Oxygen in 1 mole of C12H22O11. |
What is the mass of 45 mol of C12H22O11? |
| The molecular mass of C12H22O11 is 342.3007 g/mol. This means 342.3007 grams of C12H22O11 are present per mole. Therefore, we can find the mass of C12H22O11 in 45 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of C12H22O11 = Moles x Molar mass ∴ Mass of C12H22O11 = 45 x 342.3007 = 15403.53 g Thus, the mass of 45 mol of C12H22O11 is 15403.53 g. |
If you have 84.4595 grams of C12H22O11, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of C12H22O11 = 84.4595/342.3007 = 0.2467 Thus, there are 0.2467 moles of C12H22O11 in its 84.4595 grams. |
What is the mass in kg of 57.05 x 1025 molecules of C12H22O11? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 57.05 x 1025 molecules of C12H22O11 are: ∴ Moles of C12H22O11 = 57.05 x 1025/6.02 x 1023 = 947.7
Now that we have its number of moles, so, we can use the molar mass of C12H22O11 (342.3007 g/mol) to find its mass as shown below. ∴ Mass of C12H22O11 = Moles x Molar mass
∴ Mass of C12H22O11 = 947.7 x 342.3007 = 324390.36 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of C12H22O11 = 324390.36/1000 = 324.39 kg
The mass of 57.05 x 1025 molecules of C12H22O11 is 324.39 kg.
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What is the molar mass and molecular weight of Sucrose (C12H22O11)? |
C12H22O11 is composed of 11 Oxygen (O), 22 Hydrogen (H), and 12 Carbon (C) atoms.
To find the molecular mass of C12H22O11, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For C12H22O11, it’s (11 x 15.9994) + (22 x 1.0080) + (12 x 12.0110).
Therefore, the molar mass of Sucrose (C12H22O11) is 342.3007 g/mol.
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About the author
Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/