The molar mass and molecular weight of Sodium hydroxide (NaOH) is 39.9971 g/mol.
The composition of the NaOH formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Hydrogen | H | 1.00797 g/mol | 1 | 1.0080 g/mol | 2.5201% |
| Oxygen | O | 15.9994 g/mol | 1 | 15.9994 g/mol | 40.0014% |
| Sodium | Na | 22.98977 g/mol | 1 | 22.9898 g/mol | 57.4785% |
How to find the molar mass of Sodium hydroxide (NaOH)?
The molar mass and molecular weight of Sodium hydroxide (NaOH) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the NaOH compound.
The given compound is NaOH. It comprises atoms from 3 different elements i.e., Hydrogen (H), Oxygen (O) and Sodium (Na).
Step II: Find the atomic weight of each element in the NaOH.
Here is the list of atomic weights for all elements, let’s check the Hydrogen (H), Oxygen (O) and Sodium (Na) atom’s atomic weight.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Sodium (Na) is 22.98977 g/mol.
Step III: Determine the number of atoms of each element present in the NaOH compound.
As per the chemical formula, NaOH, It is made up of 1 Hydrogen atom, 1 Oxygen atom and 1 Sodium atom.
| Element | Number of Atoms |
|---|---|
| H (Hydrogen) | 1 |
| O (Oxygen) | 1 |
| Na (Sodium) | 1 |
Step IV: Calculate the molar mass of the Sodium hydroxide (NaOH) compound by applying the formula:
For Sodium hydroxide (NaOH):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of NaOH = [(1.00797 x 1) + (15.9994 x 1) + (22.98977 x 1)]
Molar mass of NaOH = 1.00797 + 15.999 + 22.989 = 39.9971 g/mol
Result: The molecular weight and molar mass of Sodium hydroxide (NaOH) is 39.9971 g/mol.
FAQs
What is the mass percent composition of Hydrogen (H) in Sodium hydroxide (NaOH)? |
To find the mass percent of Hydrogen in NaOH, follow the steps given below:
∴ Mass of Hydrogen in NaOH = 1.00797 x 1 = 1.0080 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in NaOH = (Mass of Hydrogen in NaOH/Molar mass of NaOH) × 100% Result: NaOH contains 2.52 % of Hydrogen as per its chemical composition.
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What is the mass percent composition of Oxygen (O) in Sodium hydroxide (NaOH)? |
To find the mass percent of Oxygen in NaOH, follow the steps given below:
∴ Mass of Oxygen in NaOH = 15.9994 x 1 = 15.9994 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in NaOH = (Mass of Oxygen in NaOH/Molar mass of NaOH) × 100% Result: NaOH contains 40.00 % of Oxygen as per its chemical composition.
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What is the mass percent composition of Sodium (Na) in Sodium hydroxide (NaOH)? |
To find the mass percent of Sodium in NaOH, follow the steps given below:
∴ Mass of Sodium in NaOH = 22.98977 x 1 = 22.9898 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Sodium in NaOH = (Mass of Sodium in NaOH/Molar mass of NaOH) × 100% Result: NaOH contains 57.48 % of Sodium as per its chemical composition.
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What is the atomic percentage composition of elements in Sodium hydroxide (NaOH)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For NaOH: The atomic percentage composition of elements in the compound is: Atomic percentage of Hydrogen (H) in NaOH: Atomic percentage of Oxygen (O) in NaOH: Atomic percentage of Sodium (Na) in NaOH:
|
How many grams of Hydrogen are present in 1 mole of NaOH? |
| There are 1 H-atoms in a NaOH molecule. • Atomic weight of a H-atom = 1.00797 g/mol ∴ Total mass of Hydrogen in 1 mole of NaOH = 1 x 1.00797 = 1.01 g. Therefore there are 1.01 grams of Hydrogen in 1 mole of NaOH. |
What is the mass of 3 mol of NaOH? |
| The molecular mass of NaOH is 39.9971 g/mol. This means 39.9971 grams of NaOH are present per mole. Therefore, we can find the mass of NaOH in 3 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of NaOH = Moles x Molar mass ∴ Mass of NaOH = 3 x 39.9971 = 119.99 g Thus, the mass of 3 mol of NaOH is 119.99 g. |
If you have 9.0074 grams of NaOH, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of NaOH = 9.0074/39.9971 = 0.2252 Thus, there are 0.2252 moles of NaOH in its 9.0074 grams. |
What is the mass in kg of 6.67 x 1025 molecules of NaOH? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 6.67 x 1025 molecules of NaOH are: ∴ Moles of NaOH = 6.67 x 1025/6.02 x 1023 = 110.7
Now that we have its number of moles, so, we can use the molar mass of NaOH (39.9971 g/mol) to find its mass as shown below. ∴ Mass of NaOH = Moles x Molar mass
∴ Mass of NaOH = 110.7 x 39.9971 = 4429.05 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of NaOH = 4429.05/1000 = 4.43 kg
The mass of 6.67 x 1025 molecules of NaOH is 4.43 kg.
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What is the molar mass and molecular weight of Sodium hydroxide (NaOH)? |
NaOH is composed of 1 Hydrogen (H), 1 Oxygen (O), and 1 Sodium (Na) atom.
To find the molecular mass of NaOH, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For NaOH, it’s (1 x 1.0080) + (1 x 15.9994) + (1 x 22.9898).
Therefore, the molar mass of Sodium hydroxide (NaOH) is 39.9971 g/mol.
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About the author
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