The molar mass and molecular weight of Selenium tetrafluoride (SeF4) is 154.9536 g/mol.
The composition of the SeF4 formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Fluorine | F | 18.998403 g/mol | 4 | 75.9936 g/mol | 49.0428% |
| Selenium | Se | 78.96 g/mol | 1 | 78.9600 g/mol | 50.9572% |
How to find the molar mass of Selenium tetrafluoride (SeF4)?
The molar mass and molecular weight of Selenium tetrafluoride (SeF4) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the SeF4 compound.
The given compound is SeF4. It comprises atoms from 2 different elements i.e., Fluorine (F) and Selenium (Se).
Step II: Find the atomic weight of each element in the SeF4.
Here is the list of atomic weights for all elements, let’s check the Fluorine (F) and Selenium (Se) atom’s atomic weight.
• The atomic weight of Fluorine (F) is 18.998403 g/mol.
• The atomic weight of Selenium (Se) is 78.96 g/mol.
Step III: Determine the number of atoms of each element present in the SeF4 compound.
As per the chemical formula, SeF4, It is made up of 4 Fluorine atoms and 1 Selenium atom.
| Element | Number of Atoms |
|---|---|
| F (Fluorine) | 4 |
| Se (Selenium) | 1 |
Step IV: Calculate the molar mass of the Selenium tetrafluoride (SeF4) compound by applying the formula:
For Selenium tetrafluoride (SeF4):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of SeF4 = [(18.998403 x 4) + (78.96 x 1)]
Molar mass of SeF4 = 75.993612 + 78.96 = 154.9536 g/mol
Result: The molecular weight and molar mass of Selenium tetrafluoride (SeF4) is 154.9536 g/mol.
FAQs
What is the mass percent composition of Fluorine (F) in Selenium tetrafluoride (SeF4)? |
To find the mass percent of Fluorine in SeF4, follow the steps given below:
∴ Mass of Fluorine in SeF4 = 18.998403 x 4 = 75.9936 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Fluorine in SeF4 = (Mass of Fluorine in SeF4/Molar mass of SeF4) × 100% Result: SeF4 contains 49.04 % of Fluorine as per its chemical composition.
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What is the mass percent composition of Selenium (Se) in Selenium tetrafluoride (SeF4)? |
To find the mass percent of Selenium in SeF4, follow the steps given below:
∴ Mass of Selenium in SeF4 = 78.96 x 1 = 78.9600 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Selenium in SeF4 = (Mass of Selenium in SeF4/Molar mass of SeF4) × 100% Result: SeF4 contains 50.96 % of Selenium as per its chemical composition.
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What is the atomic percentage composition of elements in Selenium tetrafluoride (SeF4)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For SeF4: The atomic percentage composition of elements in the compound is: Atomic percentage of Fluorine (F) in SeF4: Atomic percentage of Selenium (Se) in SeF4:
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How many grams of Fluorine are present in 1 mole of SeF4? |
| There are 4 F-atoms in a SeF4 molecule. • Atomic weight of a F-atom = 18.998403 g/mol ∴ Total mass of Fluorine in 1 mole of SeF4 = 4 x 18.998403 = 75.99 g. Therefore there are 75.99 grams of Fluorine in 1 mole of SeF4. |
What is the mass of 5 mol of SeF4? |
| The molecular mass of SeF4 is 154.9536 g/mol. This means 154.9536 grams of SeF4 are present per mole. Therefore, we can find the mass of SeF4 in 5 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of SeF4 = Moles x Molar mass ∴ Mass of SeF4 = 5 x 154.9536 = 774.77 g Thus, the mass of 5 mol of SeF4 is 774.77 g. |
If you have 49.9891 grams of SeF4, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of SeF4 = 49.9891/154.9536 = 0.3226 Thus, there are 0.3226 moles of SeF4 in its 49.9891 grams. |
What is the mass in kg of 25.83 x 1025 molecules of SeF4? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 25.83 x 1025 molecules of SeF4 are: ∴ Moles of SeF4 = 25.83 x 1025/6.02 x 1023 = 429.0
Now that we have its number of moles, so, we can use the molar mass of SeF4 (154.9536 g/mol) to find its mass as shown below. ∴ Mass of SeF4 = Moles x Molar mass
∴ Mass of SeF4 = 429.0 x 154.9536 = 66474.59 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of SeF4 = 66474.59/1000 = 66.47 kg
The mass of 25.83 x 1025 molecules of SeF4 is 66.47 kg.
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What is the molar mass and molecular weight of Selenium tetrafluoride (SeF4)? |
SeF4 is composed of 4 Fluorine (F), and 1 Selenium (Se) atom.
To find the molecular mass of SeF4, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For SeF4, it’s (4 x 18.9984) + (1 x 78.9600).
Therefore, the molar mass of Selenium tetrafluoride (SeF4) is 154.9536 g/mol.
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