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Molecular orbital (MO) diagram for O2 , O2+, O2-, O22+, O22-, and their bond order

If you are curious to know the chemistry behind chemical reactions and bond formation, then this article is for you.

In this article, we will discuss the formation of oxygen (O2) molecules under the light of the molecular orbital theory (MOT) – a game changer in the world of chemistry.

Additionally, we will teach you how to draw the molecular orbital diagram of O2, what is its bond order, whether it is paramagnetic or diamagnetic in nature, etc. We will also talk about the related ions (O2+, O2, O22+, and O22-).

So for this super interesting information, continue reading!

Name of molecule

Oxygen

Chemical formula

O2

Electronic configuration

1s2 2s2 2p4

Molecular orbital electronic configuration

(σ1s2)(σ*1s2)(σ2s2)(σ*2s2) (σ 2pz2) (π2px2)(π2py2)(π*2px1) (π*2py1)

Number of electrons in bonding MOs

10

Number of electrons in anti-bonding MOs

6

Bond order

2

Paramagnetic or Diamagnetic?

Paramagnetic

How to draw the molecular orbital (MO) diagram of O2 with its bond order?

As per the molecular orbital theory (MOT) of chemical bonding, after bond formation, the individual atomic orbitals cease to exist. Rather, the atomic orbitals of constituent atoms combine to form a unique set of molecular orbitals (MOs).

The electrons of the participant atoms are thus held in these MOs, belonging to the entire molecule in unison.

The linear combination of atomic orbitals (LCAO) produces two types of molecular orbitals:

  • Bonding molecular orbitals
  • Anti-bonding molecular orbitals

The number of MOs produced is exactly equal to the number of atomic orbitals coming together.

A bonding molecular orbital is formed by the linear combination of two AOs in the same phase.

Contrarily, an antibonding molecular orbital is produced by the linear combination of two AOs in the opposite phase, counteracting the cohesive forces of the combining nuclei.

formation of bonding and antibonding Molecular orbital diagram (MO) for O2

This is why, a bonding MO always lies at a lower energy (greater stability) than the parent AOs while an antibonding MO occupies an energy level higher than that of parent AOs (higher instability).

The electrons are filled in these MOs following the three simple rules:

  1. Aufbau Principle: Electrons first occupy the lower energy orbitals followed by their placement in the higher energy molecular orbitals.
  2. Hund’s Rule: The incoming electrons are singly filled in the degenerate MOs before pairing occurs.
  3. Pauli Exclusion Principle: Two electrons placed in the same MO exhibit an opposite spin (clockwise and anticlockwise).

The different numbers of electrons present in the bonding and/or antibonding MOs of a molecule are represented in the form of an energy level diagram called the molecular orbital (MO) diagram.

The MO diagram in turn helps in predicting other useful properties of molecules such as their bond order, stability, magnetic behavior, etc.

Oxygen (O2) is a homonuclear diatomic molecule. Two O-atoms combine to form an O2 molecule.

We can easily draw the MO diagram of O2 following the steps given below.

Steps for drawing the molecular orbital (MO) diagram of O2 with its bond order

1. Write down the electronic configuration of O2 atoms

O2 consists of two oxygen (O) atoms.

The electronic configuration of each O-atom is 1s2 2s2 2px1 2py1 2pz2.

Usually, only the valence electrons are displayed in the MO diagram of a molecule, therefore, it is important to note that each O-atom contains 6 valence electrons.

2. Determine whether the molecule is homonuclear or heteronuclear

O2 is a neutral molecule. It is homonuclear as it is formed by two atoms of the same element.

As per the rule of LCAO, the two 1s atomic orbitals of oxygen overlap to form two molecular orbitals i.e., a bonding molecular orbital (σ1s) and an antibonding molecular orbital (σ*1s).

Similarly, two 2s atomic orbitals combine to form two MOs, σ2s and σ*2s. Finally, the three 2p atomic orbitals from each O-atom combine to form six MOs including three bonding MOs (σ2pz, π2px, and  π2py) and three anti-bonding MOs (π*2px, π*2py, and σ*2pz).

The MOs discussed above are located on the MO diagram in an increasing energy order.

energy level diagram of O2

3. Fill the molecular orbitals of O2 with electrons following the energy and bonding principles

A total of 4 electrons are present in the 1s atomic orbitals of two oxygen atoms. Therefore, as per the Aufbau principle, the first two electrons go in the lowest energy σ1s MO, and the remaining two are accommodated in σ*1s.

Similarly, the 4 electrons in the 2s atomic orbitals, are uniformly distributed between σ2s and σ*2s molecular orbitals of O2.

In contrast, there are a total of 4 + 4 = 8 electrons in the 2p atomic orbitals of two O-atoms. Thus, the first two electrons are accommodated in σ2pz while the next two are placed in π2px and π2py and consequently paired up.

2 + 2 + 2 = 6 leaves behind 8 – 6 = 2 valence electrons which are finally placed in the high energy antibonding MOs (π*2px and π*2py), one in each.

This successfully completes the molecular orbital diagram of O2 as shown below.

Molecular orbital diagram (MO) of Oxygen (O2) and it's bond order

Hence, the molecular orbital electronic configuration of O2 is:

(σ1s2)(σ*1s2)(σ2s2)(σ*2s2)(σ 2pz2)(π2px2)(π2py2)(π*2px1)(π*2py1)

Is O2 diamagnetic or paramagnetic?

The presence of 2 unpaired electrons in the antibonding molecular orbitals of O2 *2px and π*2py) confirms the paramagnetic nature of oxygen.

Possessing unpaired electrons, paramagnetic substances when exposed to an external magnetic field, experience a magnetic pull and behave like magnets themselves.  

Bond order of O2

The bond order formula is:

bond order formula

∴ Bond order = (Nb –Na)/2

  • Nb = Electrons present in the bonding MOs (Bonding electrons).

∴ Electrons in σ1s + σ2s + σ2pz + π2px + π2py = 2 + 2 + 2 + 2 + 2 = 10

  • Na= Electrons present in the anti-bonding MOs (Anti-bonding electrons).

∴ Electrons in σ*1s + σ*2s + π*2px + π*2py = 2 + 2 + 1 + 1 = 6

Bond order of O2 = (10 – 6)/2 = 4/2 = 2.

Thus, there is a double covalent bond (O=O) between the two oxygen atoms in O2.

MO diagrams and bond orders of O2+, O2, O22+ and O22- 

O2+ represents a cation of oxygen. It is a molecular ion formed by the loss of 1 valence electron from the oxygen molecule.

This valence electron is removed from the least stable, highest energy atomic orbital of an O-atom i.e., 2pz.  As a result, the MO diagram of oxygen is transformed as shown below:

∴ Bond order of O2+ = (Nb –Na)/2 = (10 – 5)/2 = 2.5

Paramagnetic

O2+ Molecular orbital diagram (MO) and Bond order

Similarly, O22+ is formed by removing two electrons, one from a 2p AO of each O-atom. Therefore, both the unpaired electrons (π*2px1 and π*2py1) are removed from the O2 MO diagram to produce the O22+ MO diagram.

∴ Bond order of O22+ = (Nb –Na)/2 = (10 – 4)/2 = 3

Diamagnetic

O22+ Molecular orbital diagram (MO) and Bond order

Contrarily, O2 is a negatively charged anion. 1 extra valence electron is gained by an O-atom. This extra electron is accommodated in the antibonding MO such that π*2px gets paired up.

∴ Bond order of O2 = (Nb –Na)/2 = (10 – 7)/2 = 1.5

Paramagnetic

O2- Molecular orbital diagram (MO) and Bond order

Finally, O22- is formed when 2 extra valence electrons are gained, one by each parent O-atom. Consequently, both the antibonding MOs get paired up (π*2px + π*2py). This produces a diamagnetic molecular ion with a bond order of:

Bond order of O22- = (Nb –Na)/2 = (10 – 8)/2 = 1

O22- Molecular orbital diagram (MO) and Bond order

The bond order signifies the strength of a bond. Therefore, for the oxygen family, the bond strength increases in the order:

O22- < O2 < O2 < O2+ < O22+

However, an increasing bond order in turn means a decreasing bond length. Therefore, the bond lengths of the oxygen family follow the order:

O22- > O2 > O2 > O2+ > O22+

Also read:

FAQ

What is the MOT diagram of O2?

The MOT diagram of O2 is shown below.

MOT diagram of O2

Its MO electronic configuration is:

(σ1s2)(σ*1s2)(σ2s2)(σ*2s2) (σ 2pz2) (π2px2)(π2py2)(π*2px1) (π*2py1)

There are two unpaired electrons in the anti-bonding MOs of O2 therefore, it is paramagnetic in nature. The bond order of O2 is calculated as follows:

∴ Bond order of O2 = (Nb –Na)/2 = (10 – 6)/2 = 2

How is the MOT diagram of O22+ ion different from that of O2?

O22+ is a doubly positively charged ion of oxygen. It is formed by the loss of 2 valence electrons.

Therefore, the π*2px  and π*2py electrons are removed from the MO diagram of O2 to gain the MO diagram of O22+

What is the MOT electronic configuration of O22+?

The molecular orbital electronic configuration of O22+ is (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (σ 2pz2) (π2px2) (π2py2).

How many molecular orbitals are there in O2?  

O2 is a homonuclear diatomic molecule. It consists of two identical O-atoms, each possessing a total of 5 atomic orbitals.

The linear combination of 10 atomic orbitals results in 10 molecular orbitals, including 5 bonding MOs and 5 antibonding MOs.

All the 5 bonding MOs of O2 are filled with electrons. However, only 4 out of the 5 antibonding MOs of O2 contain electrons while the highest energy antibonding MO of oxygen i.e., σ *2pz is empty.

What is the number of electrons in bonding and antibonding molecular orbitals of O2?

There are 10 electrons in the bonding molecular orbitals of O2 (σ1s2, σ2s2, σ2pz2, π2px2, π2py2) and 6 electrons in the antibonding molecular orbitals of O2*1s2, σ*2s2, π*2px1, π*2py1). 

How many sigma and pi bonding and antibonding MOs are there in the O2 MO diagram?

In the MO diagram of O2, there are:

  • 3 sigma bonding MOs (σ1s, σ2s and σ2pz)
  • 3 sigma anti-bonding MOs (σ*1s, σ *2s and σ*2pz)
  • 2 pi bonding MOs (π2px and π2py)
  • 2 pi anti-bonding MOs (π*2px and π*2py )

Which out of O2, O22- and O22+ is paramagnetic? 

O2 is paramagnetic as per 2 unpaired electrons in its MO diagram.

Contrarily, both O22- and O22+ are diamagnetic in nature as all the electrons are paired in their MO diagrams.

Which of the following possesses the highest bond order: O2, O2+, O2, O22+ or O22-?   

O22+ possess the highest bond order i.e.,

Bond order of O22+ = (Nb –Na)/2 = (10 – 4)/2 = 3

Where,

  • Nb = Number of electrons in the bonding MOs
  • Na = Number of electrons in the antibonding MOs.

For the above-mentioned species, the bond order increases as follows:

O22- < O2 < O2 < O2+ < O22+

 Summary

  • Oxygen (O2) is a homonuclear diatomic molecule. Two identical O-atoms combine to form O2.
  • As per MOT, 10 atomic orbitals of individual oxygen atoms combine to form 10 molecular orbitals including 5 bonding and 5 antibonding MOs.
  • The Molecular orbital electronic configuration of O2 is (σ1s2)(σ*1s2)(σ2s2)(σ*2s2) (σ 2pz2) (π2px2)(π2py2)(π*2px1) (π*2py1).
  • The presence of 2 unpaired electrons in the π2p antibonding MOs of O2 means it is paramagnetic in nature.
  • The bond order of O2 is 2 which means there is a double covalent bond between two O-atoms in the O2
  • O2+, O2, O22+, and O22- are molecular ions formed by the loss or gain of electrons in the valence shell atomic orbitals of individual O-atoms.
  • The bond order follows the ascending pattern: O22- < O2 < O2 < O2+ < O22+ e., 1, 1.5, 2, 2.5, and 3 respectively.
  • O2+ and O2 are both paramagnetic while O22+ and O22- are diamagnetic in nature.
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Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/

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