Net ionic equation Calculator
Net ionic equation calculator is an online tool to “get an equation that depicts only the molecules or ions that are actively involved in the reaction or those that undergo a change.” The net ionic equation calculator is a great tool to see the active molecule in reaction.
A net ionic equation represents only the ions actually taking part in the chemical reaction, eliminating spectator ions.
[Spectator ions are the ions that do not participate in the chemical reaction rather, they stay unchanged on both the reactant and the product side of the complete ionic equation.]
|The net ionic equation calculator tool includes the 20 important equations, select any of these by clicking on the dropdown box, once you selected, the net ionic equation calculator tool will show the all steps involved in calculating the net ionic equation for a given equation.|
Net ionic equation Calculator
How to calculate a net ionic equation?
You can follow the following simple steps while calculating a net ionic equation.
- Write the complete ionic equation from the chemical reaction equation.
- Identify the spectator ions from the complete ionic equation.
- Cancel out the spectator ions on both sides of the equation.
- Obtain the net ionic equation.
Let’s understand the process of writing net ionic equations with the help of examples.
Step 1: Write the complete ionic equation from the chemical reaction equation.
For example, a chemical reaction takes place between copper (II) sulfate and sodium chloride in aqueous forms.
The chemical formula for copper (II) sulfate is CuSO4 while the chemical formula for sodium chloride is NaCl.
The chemical reaction between CuSO4 and NaCl can be represented by the balanced chemical equation shown below.
On the reactant side, CuSO4 dissociates into Cu2+ and SO42- ions in an aqueous solution. Similarly, 2 NaCl dissociates into 2 Na+ and 2 Cl– ions in the aqueous solution.
On the product side, Na2SO4 dissociates into 2 Na+ and SO42- while CuCl2 is a precipitate (it is in the solid form) so it will not dissociate into its respective ions and stay as it is.
So, the chemical equation given above can be written as a complete ionic equation, as shown below.
Step 2: Identify the spectator ions from the complete ionic equation.
In the equation above, you can see that 2 Na+ ions and an SO42- ion stays unchanged on both the reactant and the product sides.
As these ions stay uninvolved during the chemical reaction therefore they are marked as spectator ions.
Step 3: Cancel out the spectator ions on both sides of the equation
Make sure to check that the net ionic equation is a balanced equation.
Step 4: Obtain the net ionic equation
So, the balanced net ionic equation for this reaction is:
Using all the steps given above, practice with us some more examples for a better understanding of calculating net ionic equations.
Examples of Net ionic equations
A complete neutralization reaction takes place between sodium hydroxide (NaOH) and hydrochloric acid (HCl). A balanced chemical equation for the reaction is given below.
NaOH dissociates into Na+ and OH– ions while HCl dissociates into H+ and Cl– on the reactant side. While on the product side, NaCl is also water soluble so it breaks down into Na+ and Cl– ions in the presence of H2O. So the complete ionic equation for this reaction is:
This net ionic equation shows that an acid-base neutralization reaction actually takes place between hydrogen (H+) and hydroxide (OH–) ions only.
A neutralization reaction takes place between magnesium hydroxide Mg(OH)2 and sulfuric acid (H2SO4). A balanced chemical equation for the reaction is given below.
Mg(OH)2 dissociates into Mg2+ and 2 OH– ions while H2SO4 dissociates into 2 H+ and SO42- on the reactant side. While on the product side, MgSO4 formed is a water-soluble ionic compound so it dissociates into Mg2+ and SO42- ions under aqueous conditions. Thus, the complete ionic equation for this reaction is:
Lead (II) nitrate Pb(NO3)2 reacts with potassium iodide (KI) to yield potassium nitrate and a bright yellow precipitate of lead iodide (PbI2).
Pb(NO3)2 dissociates into Pb2+ and 2 NO3– ions while 2 KI dissociates into 2 K+ and 2 I– ions on the reactant side. 2 KNO3 dissociates into 2 K+ and 2 NO3– ions while PbI2 stays intact on the product side as it is a precipitate. So the complete ionic equation for this reaction is:
Sodium chloride (NaCl) reacts with silver nitrate (AgNO3) to yield a white silver chloride (AgCl) precipitate while sodium nitrate (NaNO3) is formed as the by-product.
NaCl dissociates into Na+ and Cl– ions while AgNO3 dissociates into Ag+ and NO3– ions on the reactant side. NaNO3 dissociates into Na+ and NO3– ions while AgCl stays intact on the product side. So the complete ionic equation for this reaction is:
Notice that we have placed the Ag+ ion first and then the Cl– ion is written in the net ionic equation. This is because the convention is that the positively charged cation is written prior to the negatively charged ion on the reactant side while writing net ionic equations. However, this rule is not compulsory.
You should also keep in mind that in addition to the same moles of an element on both reactant and product sides, the positive and negative charges should also be balanced, as you can ensure from any of the net ionic equations we have discussed in this article.
Now, let’s see another example.
Copper (II) chloride (CuCl2) reacts with sodium phosphate (Na3PO4) to produce a blue solid precipitate known as copper (II) phosphate and sodium chloride.
3 CuCl2 dissociates into 3 Cu2+ and 6 Cl– ions while 2 Na3PO4 dissociates into 6 Na+ and 2 PO43- ions on the reactant side. 6 NaCl dissociates into 6 Na+ and 6 Cl– ions while Cu3(PO4)2 stays unchanged on the product side. So the complete ionic equation for this reaction is:
Positive and negative charges on both sides of the ionic equation are balanced.
You may note that the positive and negative charges are also balanced in this net ionic equation i.e., +6 and -6 respectively on both sides of the equation.
Lead nitrate Pb(NO3)2 reacts with lithium bromide (LiBr). As a result, lithium nitrate (LiNO3) and lead bromide (PbBr2) are produced, as shown in the chemical equation given below.
Now in the above equation, the physical state symbols of all the reactants and products are not given. In such a situation, you need to identify which of the reactants and products are water soluble while others are not.
Applying the solubility rules, we will identify that lead bromide appears as a white solid as r.t.p. It has very low solubility in water i.e., 0.455 g per 100 g H2O. Therefore, in the above chemical reaction, PbBr2 is the precipitate obtained. All the other compounds are water soluble so they appear as aqueous solutions.
Pb(NO3)2 dissociates into Pb2+ and 2 NO3– ions while 2 LiBr dissociates into 2 Li+ and 2 Br– ions on the reactant side. 2 LiNO3 dissociates into 2 Li+ and 2 NO3– ions while PbBr2 stays undissociated on the product side. So the complete ionic equation for this reaction is:
A chemical reaction between sodium iodide (NaI) and calcium nitrate Ca(NO3)2 produces an aqueous solution of sodium nitrate (NaNO3) and calcium iodide (CaI2).
Now in this reaction, no precipitates are formed. So, all the ionic compounds will dissociate into their ions both on the reactant as well as the product side.
2 NaI dissociates into 2 Na+ and 2 I– ions while Ca(NO3)2 dissociates into Ca2+ and 2 NO3– ions on the reactant side. While on the product side, 2 NaNO3 dissociates into 2 Na+ and 2 NO3– ions while CaI2 breaks down to produce Ca2+ and 2 I– ions.
All the ions here prove to be spectator ions, so all the ions are canceled out. Thus, there is no such reaction. So no net ionic equation.
What does the net ionic equation represent?
|A net ionic equation represents only the ions actually taking part in the chemical reaction, eliminating spectator ions.|
What is a net ionic equation calculator?
|The net ionic equation calculator is an online tool that shows the “chemical equation”, “complete ionic equation”, “Cancellation of spectator ions”, and a “Net ionic equation”.|
What is the difference between the Balanced and net ionic equation?
The balanced equation shows all the details about species that are in the system. It gives the actual number of molecules of each reactant and product.
Whereas the net ionic equation shows only species that take part in the reaction, it doesn’t show the spectator’s ions.
You can easily balance the chemical equation by using this tool given below –
About the author
Welcome to Topblogtenz, My name is Vishal Goyal. I am an engineer, chemistry tutor, blogger, and founder of topblogtenz.com. I'm a science geek with a passion for life sciences and chemistry. Being a chemistry tutor and having a degree in Engineering, I know how hard it is to learn by yourself, that is why I created a site where you can find help related to science and chemistry before everyone else.