Is CH3CH2CH2OH polar or nonpolar? – (Polarity of 1-propanol)

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The question is –

Is 1-propanol (CH3CH2CH2OH) polar or nonpolar?

Answer:

1-propanol (CH3CH2CH2OH) is polar.  

Explanation:

1-propanol or propan-1-ol (CH3CH2CH2OH) is a polar primary alcohol as it consists of a strongly polar hydroxyl (OH) functional group in it.

The strong dipole moments of C-O and O-H bonds do not get canceled with the weak dipole moments of C-H bonds.

CH3CH2CH2OH is a primary alcohol as the hydroxyl (OH) functional group is present at the terminal position i.e., attached to the C-atom carrying one alkyl chain only.

It is composed of 1 O-H bond, 1 C-O bond, 2 C-C bonds, and 7 C-H bonds.

Each C-C bond is purely non-polar as it consists of two identical carbon atoms having zero or no electronegativity differences.

A C-H bond is very weakly polar as the covalently bonded carbon (E.N = 2.55), and hydrogen (E.N = 2.20) atoms have an electronegativity difference of only 0.35 units.

 A C-O bond is strongly polar as an electronegativity difference of 0.89 units is present between a carbon and an oxygen (E.N = 3.44) atom.

The O-H bond is extremely polar, having an electronegativity difference of 1.24 units between the oxygen and hydrogen atoms.

The shape of CH3CH2CH2OH w.r.t each C-atom is tetrahedral while that w.r.t the O-atom is bent, angular, or V-shaped.

2 lone pairs of electrons present on the oxygen atom lead to strong lone pair-lone pair and lone pair-bond pair electronic repulsions, which in turn distorts the shape and geometry of the molecule.

Oxygen being strongly electronegative attracts electrons from each C-H bond in addition to attracting the O-H and C-O bonded electrons.

The O-atom thus gains a partial negative charge (δ), while the C and H-atoms gain partial positive charges (δ+ and/or δ++) to denote an extreme electron deficiency.

Is 1-propanol (CH3CH2CH2OH) polar or nonpolar

The strong O-H and C-O dipole moments do not get canceled equally.

The charged electron cloud stays non-uniformly distributed, which leads to an overall polar CH3CH2CH2OH molecule (net µ > 0).

Also, check –

How to identify polar or nonpolar compounds?

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