How to find Keq? - Equilibrium constant
The symbol Keq represents the equilibrium constant. Keq helps in understanding the behavior of a chemical reaction at equilibrium under varying concentration, temperature, and pressure conditions.
What is Keq?
In chemistry, a reversible reaction is one that takes place in both forward as well as backward directions simultaneously.
aA + bB ⇌ cC + dD
Dynamic equilibrium is a state of balance achieved when the rate of forward reaction becomes equal to the rate of backward reaction.
Keq helps in predicting quantitatively to what extent the reaction proceeds in the forward or reverse direction.
In this article, we will teach you how to calculate Keq, what the different types of equilibrium constants are and when to use which one, using some examples.
So for all this valuable information, continue reading!
What are the different types of Keq?
For the reversible reaction aA + bB ⇌ cC + dD, where a moles of A react with b moles of B to produce c moles of C and d moles of D, the equilibrium constant (Keq) can be expressed as:
Where,
- [A] = Molar concentration of reactant A at equilibrium (Units: mol/dm3 or mol/L)
- [B] = Molar concentration of reactant B at equilibrium (Units: mol/dm3 or mol/L)
- [C] = Molar concentration of reactant C at equilibrium (Units: mol/dm3 or mol/L)
- [D] = Molar concentration of reactant D at equilibrium (Units: mol/dm3 or mol/L)
As per equation (i), Keq is defined as the ratio of the product of the molar concentration of products to the product of the molar concentration of reactants.
All the reactant and product concentrations are raised to the number of moles of each in the balanced chemical equation.
The equilibrium constant (Keq) expressed in terms of molar concentrations is denoted as Kc.
Kc represents the relative amount of reactants and products at equilibrium.
The units of Kc are subjective. It depends upon the total number of reactants and products participating in the reversible chemical reaction.
For example, let’s see how we can express Keq for the reaction given below and what are its units.
- If Keq > 1: Forward reaction (Reactants → Products) is favored.
- If Keq < 1: Backward reaction (Products → Reactants) is favored.
- If Keq = 1: The reaction stays at equilibrium (Reactants ⇌ Products)
- If Keq → ∞: The reaction becomes irreversible
If gaseous reactants and/or products are involved in a chemical reaction, the equilibrium constant (Keq) can be expressed in terms of partial pressures. In this case, Keq is denoted as Kp.
For the reversible reaction aA (g) + bB (g) ⇌ cC (g) + dD (g)
……equation (ii)
Where;
- PA = Partial pressure of A (Units: Pa or atm)
- PB = Partial pressure of B (Units: Pa or atm)
- PC = Partial pressure of C (Units: Pa or atm)
- PD = Partial pressure of D (Units: Pa or atm)
Partial pressure is defined as the pressure exerted (force/area) by one of the gases in a gaseous mixture.
However, you must keep in mind that equation (ii) is only applicable to gaseous components in the chemical reaction.
For example,
PCl5 (g) ⇌ PCl3 (g) + Cl2 (g)
For the above reaction, the Kp expression is:
K_{eq} = K_p = \frac{P_{\mathrm{PCl_3}} \times P_{\mathrm{Cl_2}}}{{P_{\mathrm{PCl_5}}}}
Contrarily,
C(s) + H2O (g) ⇌ H2 (g) + CO (g)
In this case, carbon (C) is not a gaseous component, so it is omitted in the Kp expression. The Kp expression thus reduces to:
K_{eq} = K_p = \frac{{P_{\mathrm{H_2}}}^{1} \cdot {P_{\mathrm{CO}}}^{1}}{{P_{\mathrm{H_2O}}}^{1}}
Similarly, the units of Kp are variable, depending upon the total number of gaseous components involved and their mole ratio.
Kp is related to Kc by equation (iii).
Kp = Kc (RT) ∆n…Equation (iii)
Where;
- Kp = Keq in terms of partial pressures
- Kc = Keq in terms of molar concentrations
- R = Ideal gas constant (R= 8.314 J/K.mol)
- T = Absolute temperature
- ∆n = Difference in the number of moles from the reactant to the product side
If ∆n = 0, then two equilibrium constants become equal, i.e., Kp = Kc.
How to calculate Keq? – Examples
Keq can be calculated using any of the equations (i), (ii), or (iii) depending upon the information provided in the question statement.
Let us see how through the examples given below.
Example # 1: The reaction shown below was allowed to reach equilibrium. 2 NO(g) + 2 H2 (g) ⇌ N2(g) + 2 H2O(g) Find the equilibrium constant (Keq) for the reaction given that the initial concentrations of NO and H2 were 0.100 mol/dm3 and 0.050 mol/dm3 in the reaction mixture, while the equilibrium concentration of NO was 0.062 mol/dm3. |
Solution: To find the equilibrium constant (Keq), we first need to have the equilibrium concentrations of all reactants and products. We can find that by using the balanced chemical equation and the initial concentrations given in the question statement. ⇒ Equilibrium concentration of N2 = x = 0.019 mol/dm3 ⇒ Equilibrium concentration of H2O = 2x = 2(0.019)= 0.038 mol/dm3 ⇒ Equilibrium concentration of H2 = 0.050 – x = 0.050 – 0.019 = 0.031 mol/dm3 Result: The equilibrium constant (Keq) for the given reaction is 7.4 mol-1dm3. Further insight: Keq > 1 implies that the reaction proceeds forward. |
Example # 2: W.r.t the reaction shown below, at the equilibrium stage, the partial pressure of nitrogen, hydrogen, and ammonia gas was recorded to be 0.094 atm, 0.039 atm, and 0.003 atm, respectively. Find the equilibrium constant (Keq) for the reaction. N2 (g) + 3 H2 (g) ⇌ 2 NH3 (g) |
Solution: Result: The equilibrium constant (Keq) for the given reaction is 1.61 atm-2. |
FAQ
How do you calculate Keq? |
Keq can be calculated from the molar concentrations of reactants and products by applying the formula given below: K_{eq} = \frac{[Products]}{[Reactants]} For a reversible chemical reaction: aA + bB ⇌ cC + dD If gaseous components are involved in a heterogeneous chemical reaction, Keq can be expressed in terms of partial pressures (P) of the gases and calculated by using the formula given below: |
What are the different formulae for finding equilibrium constant (Keq)? |
The four most important formulae for Keq are: The relationship between two equilibrium constants: Kc = Kp (RT)∆n Equilibrium constant in terms of Gibbs free energy change: ∆G = -nRT lnKeq Any of the above formulae can be used to find the equilibrium constant (Keq) under different situations. |
How do you calculate Keq from pKa? |
A weak acid (HA) partially dissociates in water (H2O), as shown below: HA + H2O ⇌ A– + H3O+ The equilibrium constant (Keq) for the above equation can be expressed as: K_{eq} = \frac{[A^-][H_3O^+]}{[HA][H_2O]} In this case, Keq is called Ka (acid dissociation constant) pKa = -log10Keq Thus, Keq can be calculated by taking the antilog of pKa: ∴ Keq = 10-pKa |
How temperature affects Keq for a reaction? |
As per Le –Chattlier’s principle, increasing temperature shifts the equilibrium in the direction in which heat is absorbed (i.e., endothermic side), thus directly affecting Keq. For instance, in the reaction shown below: N2 (g) + 3 H2 (g) ⇌ 2 NH3(g) ∆H = -92.4 kJ/mol Increasing temperature shifts the equilibrium backward [product] decreases, which decreases Keq and vice versa. |
How a catalyst affects Keq for a reaction? |
There is no effect of a catalyst on the Keq of a reaction, as adding a catalyst increases both the rate of the forward and backward reactions to the same extent. |
About the author
Ammara Waheed is a highly qualified and experienced chemist, whose passion for Chemistry is evident in her writing. With a Bachelor of Science (Hons.) and Master of Philosophy (M. Phil) in Physical and Analytical Chemistry from Government College University (GCU) Lahore, Pakistan, with a hands-on laboratory experience in the Pakistan Council of Scientific and Industrial Research (PCSIR), Ammara has a solid educational foundation in her field. She comes from a distinguished research background and she documents her research endeavors for reputable journals such as Wiley and Elsevier. Her deep knowledge and expertise in the field of Chemistry make her a trusted and reliable authority in her profession. Let's connect - https://www.researchgate.net/profile/Ammara-Waheed
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