The molar mass and molecular weight of Formaldehyde (H2CO) is 30.0263 g/mol.
The composition of the H2CO formula is as follows:
Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
---|---|---|---|---|---|
Oxygen | O | 15.9994 g/mol | 1 | 15.9994 g/mol | 53.2845% |
Carbon | C | 12.011 g/mol | 1 | 12.0110 g/mol | 40.0015% |
Hydrogen | H | 1.00797 g/mol | 2 | 2.0159 g/mol | 6.7139% |
How to find the molar mass of Formaldehyde (H2CO)?
The molar mass and molecular weight of Formaldehyde (H2CO) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the H2CO compound.
The given compound is H2CO. It comprises atoms from 3 different elements i.e., Oxygen (O), Carbon (C) and Hydrogen (H).
Step II: Find the atomic weight of each element in the H2CO.
Here is the list of atomic weights for all elements, let’s check the Oxygen (O), Carbon (C) and Hydrogen (H) atom’s atomic weight.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
Step III: Determine the number of atoms of each element present in the H2CO compound.
As per the chemical formula, H2CO, It is made up of 1 Oxygen atom, 1 Carbon atom and 2 Hydrogen atoms.
Element | Number of Atoms |
---|---|
O (Oxygen) | 1 |
C (Carbon) | 1 |
H (Hydrogen) | 2 |
Step IV: Calculate the molar mass of the Formaldehyde (H2CO) compound by applying the formula:
For Formaldehyde (H2CO):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of H2CO = [(15.9994 x 1) + (12.011 x 1) + (1.00797 x 2)]
Molar mass of H2CO = 15.9994 + 12.011 + 2.01594 = 30.0263 g/mol
Result: The molecular weight and molar mass of Formaldehyde (H2CO) is 30.0263 g/mol.
FAQs
What is the mass percent composition of Oxygen (O) in Formaldehyde (H2CO)? |
To find the mass percent of Oxygen in H2CO, follow the steps given below:
∴ Mass of Oxygen in H2CO = 15.9994 x 1 = 15.9994 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in H2CO = (Mass of Oxygen in H2CO/Molar mass of H2CO) × 100% Result: H2CO contains 53.28 % of Oxygen as per its chemical composition. |
What is the mass percent composition of Carbon (C) in Formaldehyde (H2CO)? |
To find the mass percent of Carbon in H2CO, follow the steps given below:
∴ Mass of Carbon in H2CO = 12.011 x 1 = 12.0110 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in H2CO = (Mass of Carbon in H2CO/Molar mass of H2CO) × 100% Result: H2CO contains 40.00 % of Carbon as per its chemical composition. |
What is the mass percent composition of Hydrogen (H) in Formaldehyde (H2CO)? |
To find the mass percent of Hydrogen in H2CO, follow the steps given below:
∴ Mass of Hydrogen in H2CO = 1.00797 x 2 = 2.0159 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in H2CO = (Mass of Hydrogen in H2CO/Molar mass of H2CO) × 100% Result: H2CO contains 6.71 % of Hydrogen as per its chemical composition. |
What is the atomic percentage composition of elements in Formaldehyde (H2CO)? |
Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For H2CO: The atomic percentage composition of elements in the compound is: Atomic percentage of Oxygen (O) in H2CO: Atomic percentage of Carbon (C) in H2CO: Atomic percentage of Hydrogen (H) in H2CO: |
How many grams of Oxygen are present in 1 mole of H2CO? |
There are 1 O-atoms in a H2CO molecule. • Atomic weight of a O-atom = 15.9994 g/mol ∴ Total mass of Oxygen in 1 mole of H2CO = 1 x 15.9994 = 16.00 g. Therefore there are 16.00 grams of Oxygen in 1 mole of H2CO. |
What is the mass of 4 mol of H2CO? |
The molecular mass of H2CO is 30.0263 g/mol. This means 30.0263 grams of H2CO are present per mole. Therefore, we can find the mass of H2CO in 4 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of H2CO = Moles x Molar mass ∴ Mass of H2CO = 4 x 30.0263 = 120.11 g Thus, the mass of 4 mol of H2CO is 120.11 g. |
If you have 22.0047 grams of H2CO, how many moles do you have? |
∴ Moles = Mass/Molar mass ∴ Moles of H2CO = 22.0047/30.0263 = 0.7328 Thus, there are 0.7328 moles of H2CO in its 22.0047 grams. |
What is the mass in kg of 5.00 x 1025 molecules of H2CO? |
1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 5.00 x 1025 molecules of H2CO are: ∴ Moles of H2CO = 5.00 x 1025/6.02 x 1023 = 83.1
Now that we have its number of moles, so, we can use the molar mass of H2CO (30.0263 g/mol) to find its mass as shown below. ∴ Mass of H2CO = Moles x Molar mass
∴ Mass of H2CO = 83.1 x 30.0263 = 2496.07 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of H2CO = 2496.07/1000 = 2.50 kg
The mass of 5.00 x 1025 molecules of H2CO is 2.50 kg.
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What is the molar mass and molecular weight of Formaldehyde (H2CO)? |
H2CO is composed of 1 Oxygen (O), 1 Carbon (C), and 2 Hydrogen (H) atoms.
To find the molecular mass of H2CO, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For H2CO, it’s (1 x 15.9994) + (1 x 12.0110) + (2 x 1.0080).
Therefore, the molar mass of Formaldehyde (H2CO) is 30.0263 g/mol. |
About the author
Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/