The molar mass and molecular weight of Camphor (C10H16O) is 152.2369 g/mol.
The composition of the C10H16O formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Oxygen | O | 15.9994 g/mol | 1 | 15.9994 g/mol | 10.5095% |
| Hydrogen | H | 1.00797 g/mol | 16 | 16.1275 g/mol | 10.5937% |
| Carbon | C | 12.011 g/mol | 10 | 120.1100 g/mol | 78.8968% |
How to find the molar mass of Camphor (C10H16O)?
The molar mass and molecular weight of Camphor (C10H16O) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the C10H16O compound.
The given compound is C10H16O. It comprises atoms from 3 different elements i.e., Oxygen (O), Hydrogen (H) and Carbon (C).
Step II: Find the atomic weight of each element in the C10H16O.
Here is the list of atomic weights for all elements, let’s check the Oxygen (O), Hydrogen (H) and Carbon (C) atom’s atomic weight.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
Step III: Determine the number of atoms of each element present in the C10H16O compound.
As per the chemical formula, C10H16O, It is made up of 1 Oxygen atom, 16 Hydrogen atoms and 10 Carbon atoms.
| Element | Number of Atoms |
|---|---|
| O (Oxygen) | 1 |
| H (Hydrogen) | 16 |
| C (Carbon) | 10 |
Step IV: Calculate the molar mass of the Camphor (C10H16O) compound by applying the formula:
For Camphor (C10H16O):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of C10H16O = [(15.9994 x 1) + (1.00797 x 16) + (12.011 x 10)]
Molar mass of C10H16O = 15.9994 + 16.12752 + 120.109 = 152.2369 g/mol
Result: The molecular weight and molar mass of Camphor (C10H16O) is 152.2369 g/mol.
FAQs
What is the mass percent composition of Oxygen (O) in Camphor (C10H16O)? |
To find the mass percent of Oxygen in C10H16O, follow the steps given below:
∴ Mass of Oxygen in C10H16O = 15.9994 x 1 = 15.9994 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in C10H16O = (Mass of Oxygen in C10H16O/Molar mass of C10H16O) × 100% Result: C10H16O contains 10.51 % of Oxygen as per its chemical composition.
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What is the mass percent composition of Hydrogen (H) in Camphor (C10H16O)? |
To find the mass percent of Hydrogen in C10H16O, follow the steps given below:
∴ Mass of Hydrogen in C10H16O = 1.00797 x 16 = 16.1275 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in C10H16O = (Mass of Hydrogen in C10H16O/Molar mass of C10H16O) × 100% Result: C10H16O contains 10.59 % of Hydrogen as per its chemical composition.
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What is the mass percent composition of Carbon (C) in Camphor (C10H16O)? |
To find the mass percent of Carbon in C10H16O, follow the steps given below:
∴ Mass of Carbon in C10H16O = 12.011 x 10 = 120.1100 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in C10H16O = (Mass of Carbon in C10H16O/Molar mass of C10H16O) × 100% Result: C10H16O contains 78.90 % of Carbon as per its chemical composition.
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What is the atomic percentage composition of elements in Camphor (C10H16O)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For C10H16O: The atomic percentage composition of elements in the compound is: Atomic percentage of Oxygen (O) in C10H16O: Atomic percentage of Hydrogen (H) in C10H16O: Atomic percentage of Carbon (C) in C10H16O:
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How many grams of Oxygen are present in 1 mole of C10H16O? |
| There are 1 O-atoms in a C10H16O molecule. • Atomic weight of a O-atom = 15.9994 g/mol ∴ Total mass of Oxygen in 1 mole of C10H16O = 1 x 15.9994 = 16.00 g. Therefore there are 16.00 grams of Oxygen in 1 mole of C10H16O. |
What is the mass of 27 mol of C10H16O? |
| The molecular mass of C10H16O is 152.2369 g/mol. This means 152.2369 grams of C10H16O are present per mole. Therefore, we can find the mass of C10H16O in 27 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of C10H16O = Moles x Molar mass ∴ Mass of C10H16O = 27 x 152.2369 = 4110.40 g Thus, the mass of 27 mol of C10H16O is 4110.40 g. |
If you have 46.4468 grams of C10H16O, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of C10H16O = 46.4468/152.2369 = 0.3051 Thus, there are 0.3051 moles of C10H16O in its 46.4468 grams. |
What is the mass in kg of 25.37 x 1025 molecules of C10H16O? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 25.37 x 1025 molecules of C10H16O are: ∴ Moles of C10H16O = 25.37 x 1025/6.02 x 1023 = 421.5
Now that we have its number of moles, so, we can use the molar mass of C10H16O (152.2369 g/mol) to find its mass as shown below. ∴ Mass of C10H16O = Moles x Molar mass
∴ Mass of C10H16O = 421.5 x 152.2369 = 64164.12 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of C10H16O = 64164.12/1000 = 64.16 kg
The mass of 25.37 x 1025 molecules of C10H16O is 64.16 kg.
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What is the molar mass and molecular weight of Camphor (C10H16O)? |
C10H16O is composed of 1 Oxygen (O), 16 Hydrogen (H), and 10 Carbon (C) atoms.
To find the molecular mass of C10H16O, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For C10H16O, it’s (1 x 15.9994) + (16 x 1.0080) + (10 x 12.0110).
Therefore, the molar mass of Camphor (C10H16O) is 152.2369 g/mol.
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About the author
Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/