The molar mass and molecular weight of Calcium carbonate (CaCO3) is 100.0892 g/mol.
The composition of the CaCO3 formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Oxygen | O | 15.9994 g/mol | 3 | 47.9982 g/mol | 47.9554% |
| Carbon | C | 12.011 g/mol | 1 | 12.0110 g/mol | 12.0003% |
| Calcium | Ca | 40.08 g/mol | 1 | 40.0800 g/mol | 40.0443% |
How to find the molar mass of Calcium carbonate (CaCO3)?
The molar mass and molecular weight of Calcium carbonate (CaCO3) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the CaCO3 compound.
The given compound is CaCO3. It comprises atoms from 3 different elements i.e., Oxygen (O), Carbon (C) and Calcium (Ca).
Step II: Find the atomic weight of each element in the CaCO3.
Here is the list of atomic weights for all elements, let’s check the Oxygen (O), Carbon (C) and Calcium (Ca) atom’s atomic weight.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
• The atomic weight of Calcium (Ca) is 40.08 g/mol.
Step III: Determine the number of atoms of each element present in the CaCO3 compound.
As per the chemical formula, CaCO3, It is made up of 3 Oxygen atoms, 1 Carbon atom and 1 Calcium atom.
| Element | Number of Atoms |
|---|---|
| O (Oxygen) | 3 |
| C (Carbon) | 1 |
| Ca (Calcium) | 1 |
Step IV: Calculate the molar mass of the Calcium carbonate (CaCO3) compound by applying the formula:
For Calcium carbonate (CaCO3):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of CaCO3 = [(15.9994 x 3) + (12.011 x 1) + (40.08 x 1)]
Molar mass of CaCO3 = 47.9982 + 12.011 + 40.08 = 100.0892 g/mol
Result: The molecular weight and molar mass of Calcium carbonate (CaCO3) is 100.0892 g/mol.
FAQs
What is the mass percent composition of Oxygen (O) in Calcium carbonate (CaCO3)? |
To find the mass percent of Oxygen in CaCO3, follow the steps given below:
∴ Mass of Oxygen in CaCO3 = 15.9994 x 3 = 47.9982 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in CaCO3 = (Mass of Oxygen in CaCO3/Molar mass of CaCO3) × 100% Result: CaCO3 contains 47.96 % of Oxygen as per its chemical composition.
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What is the mass percent composition of Carbon (C) in Calcium carbonate (CaCO3)? |
To find the mass percent of Carbon in CaCO3, follow the steps given below:
∴ Mass of Carbon in CaCO3 = 12.011 x 1 = 12.0110 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in CaCO3 = (Mass of Carbon in CaCO3/Molar mass of CaCO3) × 100% Result: CaCO3 contains 12.00 % of Carbon as per its chemical composition.
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What is the mass percent composition of Calcium (Ca) in Calcium carbonate (CaCO3)? |
To find the mass percent of Calcium in CaCO3, follow the steps given below:
∴ Mass of Calcium in CaCO3 = 40.08 x 1 = 40.0800 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Calcium in CaCO3 = (Mass of Calcium in CaCO3/Molar mass of CaCO3) × 100% Result: CaCO3 contains 40.04 % of Calcium as per its chemical composition.
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What is the atomic percentage composition of elements in Calcium carbonate (CaCO3)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For CaCO3: The atomic percentage composition of elements in the compound is: Atomic percentage of Oxygen (O) in CaCO3: Atomic percentage of Carbon (C) in CaCO3: Atomic percentage of Calcium (Ca) in CaCO3:
|
How many grams of Oxygen are present in 1 mole of CaCO3? |
| There are 3 O-atoms in a CaCO3 molecule. • Atomic weight of a O-atom = 15.9994 g/mol ∴ Total mass of Oxygen in 1 mole of CaCO3 = 3 x 15.9994 = 48.00 g. Therefore there are 48.00 grams of Oxygen in 1 mole of CaCO3. |
What is the mass of 5 mol of CaCO3? |
| The molecular mass of CaCO3 is 100.0892 g/mol. This means 100.0892 grams of CaCO3 are present per mole. Therefore, we can find the mass of CaCO3 in 5 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of CaCO3 = Moles x Molar mass ∴ Mass of CaCO3 = 5 x 100.0892 = 500.45 g Thus, the mass of 5 mol of CaCO3 is 500.45 g. |
If you have 36.0172 grams of CaCO3, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of CaCO3 = 36.0172/100.0892 = 0.3599 Thus, there are 0.3599 moles of CaCO3 in its 36.0172 grams. |
What is the mass in kg of 16.68 x 1025 molecules of CaCO3? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 16.68 x 1025 molecules of CaCO3 are: ∴ Moles of CaCO3 = 16.68 x 1025/6.02 x 1023 = 277.1
Now that we have its number of moles, so, we can use the molar mass of CaCO3 (100.0892 g/mol) to find its mass as shown below. ∴ Mass of CaCO3 = Moles x Molar mass
∴ Mass of CaCO3 = 277.1 x 100.0892 = 27734.91 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of CaCO3 = 27734.91/1000 = 27.73 kg
The mass of 16.68 x 1025 molecules of CaCO3 is 27.73 kg.
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What is the molar mass and molecular weight of Calcium carbonate (CaCO3)? |
CaCO3 is composed of 3 Oxygen (O), 1 Carbon (C), and 1 Calcium (Ca) atom.
To find the molecular mass of CaCO3, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For CaCO3, it’s (3 x 15.9994) + (1 x 12.0110) + (1 x 40.0800).
Therefore, the molar mass of Calcium carbonate (CaCO3) is 100.0892 g/mol.
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About the author
Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/