Molecular orbital (MO) diagram for C2 , C2-, C2+, C22+, C22-, and their bond order
If you are keen on learning how to draw the molecular orbital (MO) diagram of C2 and calculate its bond order, then come along and continue reading the article.
In this article, we will discuss the Molecular orbital diagrams of C2, C2+, C2–, C22+, and C22-, calculating their bond orders and determining some useful properties such as the bond strength, bond length, and magnetism of C2 and its related ions.
Name of molecule | Dicarbon |
Chemical formula | C2 |
Electronic configuration | 1s2 2s2 2p2 |
Molecular orbital electronic configuration | (σ1s2 )(σ*1s2) (σ2s2)(σ*2s2)(π2px2)(π2py2) |
Number of electrons in bonding MOs | 8 |
Number of electrons in anti-bonding MOs | 4 |
Bond order | 2 |
Paramagnetic or Diamagnetic? | Diamagnetic |
How to draw the molecular orbital (MO) diagram of C2 with its bond order?
As per the molecular orbital theory (MOT) of chemical bonding, after bond formation, the individual atomic orbitals cease to exist. Rather, the atomic orbitals of constituent atoms combine to form a unique set of molecular orbitals (MOs).
The electrons of the participant atoms are thus held in these MOs, belonging to the entire molecule in unison.
The linear combination of atomic orbitals (LCAO) produces two types of molecular orbitals:
- Bonding molecular orbitals
- Anti-bonding molecular orbitals
The number of MOs produced is exactly equal to the number of atomic orbitals coming together.
A bonding molecular orbital (BMO) is formed by the linear combination of two AOs in the same phase.
Contrarily, an antibonding molecular orbital (ABMO) is produced by the linear combination of two AOs in the opposite phase, counteracting the cohesive forces of the combining nuclei.
This is why, a bonding MO always lies at a lower energy (greater stability) than the parent AOs while an antibonding MO occupies an energy level higher than that of parent AOs (higher instability).
The electrons are filled in these MOs following the three simple rules:
- Aufbau Principle: Electrons first occupy the lower energy orbitals followed by their placement in the higher energy molecular orbitals.
- Hund’s Rule: The incoming electrons are singly filled in the degenerate MOs before pairing occurs.
- Pauli Exclusion Principle: Two electrons placed in the same MO exhibit an opposite spin (clockwise and anticlockwise).
The different numbers of electrons present in the bonding and/or antibonding MOs of a molecule are displayed schematically on an energy level diagram called the molecular orbital (MO) diagram.
The formula C2 represents a homonuclear diatomic molecule i.e., a molecule containing two atoms from the same element, in this case, carbon (C) from Group IV A (or 14) of the Periodic Table.
You can easily draw the MO diagram of C2 following the simple steps given below.
Steps for drawing the molecular orbital (MO) diagram of C2 with its bond order
1. Write down the electronic configuration of C2 atoms
C2 comprises two identical carbon (C) atoms.
The electronic configuration of each C-atom is 1s2 2s2 2p2.
Usually, only the valence electrons are displayed in the MO diagram of a molecule, therefore, it is important to note that each C-atom contains 4 valence electrons.
2 C-atoms combined make a total of 2(6) = 12 electrons and 2(4) = 8 valence electrons to be filled in the Molecular orbital diagram of C2.
2. Determine whether the molecule is homonuclear or heteronuclear
C2 is a neutral molecule. It is homonuclear as it is formed by two atoms of the same element.
As per the rule of LCAO, the two 1s atomic orbitals of carbon overlap to produce two molecular orbitals i.e., a bonding molecular orbital (σ1s) and an antibonding molecular orbital (σ*1s).
Similarly, two 2s atomic orbitals combine to form two MOs, σ2s and σ*2s. Finally, the three 2p atomic orbitals from each C-atom overlap to produce six MOs including three bonding MOs (π2px, π2py, and σ2pz) and three anti-bonding MOs (π*2px, π*2py, and σ*2pz).
The MOs discussed above are located on the MO diagram in an increasing energy order.
3. Fill the molecular orbitals of C2 with electrons following the energy and bonding principles
A total of 4 electrons are present in the 1s atomic orbitals of two carbon atoms. Therefore, as per the Aufbau principle, the first two electrons go in the lowest energy σ1s MO, and the remaining two are accommodated in σ*1s.
Similarly, the 4 electrons in the 2s atomic orbitals of carbon, are uniformly distributed between σ2s and σ*2s molecular orbitals of C2.
In contrast, there are a total of 2 + 2 = 4 electrons in the 2p atomic orbitals of two C-atoms.
2 out of the 4 electrons are first singly filled in the π2px and π2py MOs of C2 (Hund’s rule). These are then paired up in an opposite spin (Pauli Exclusion Principle).
However, the rest of the 2p bonding and antibonding molecular orbitals stay entirely unoccupied in the MO diagram of C2.
Hence, we have successfully filled the Molecular orbital diagram of C2 as shown below.
As per the above diagram, the Molecular orbital electronic configuration of C2 is-
(σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2)
Is C2 diamagnetic or paramagnetic?
C2 is a diamagnetic molecule as there are no unpaired electrons in its molecular orbital diagram.
Diamagnetic substances possess no permanent dipole moment value; therefore they get repelled by an external magnetic field.
Bond order of C2
The bond order formula is:
∴ Bond order = (Nb –Na)/2
- Nb = Electrons present in the bonding MOs (Bonding electrons).
∴ Electrons in σ1s + σ2s + π2px + π2py = 2 + 2 + 2 + 2 = 8
- Na= Electrons present in the anti-bonding MOs (Anti-bonding electrons).
∴ Electrons in σ*1s + σ*2s = 2 + 2 = 4
⇒ Bond order of C2 = (8 – 4)/2 = 4/2 = 2.
Bond order > 0 means C2 is stable while a bond order value of 2 implies that there is ideally a double covalent bond (C=C) between two C-atoms in the diatomic C2 molecule.
MO diagrams and bond orders of C2+, C2–, C22+ and C22-
C2+ represents a cation of the dicarbon molecule. It is a molecular ion formed by the loss of 1 valence electron from C2.
This valence electron is removed from one of the two 2p orbitals of an individual C-atom. Upon C2+ formation, the electron present in π2py gets unpaired. As a result, C2+ is paramagnetic and its Molecular orbital diagram is as shown below:
∴ Bond order of C2+ = (Nb –Na)/2 = (7 – 4)/2 = 1.5
MO electronic configuration of C2+: (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py1)
⇒ Paramagnetic
Conversely, C22+ is formed by removing two electrons, one from a 2p AO of each C-atom. Therefore, the electrons present in both π2px and π2py MOs get unpaired, producing the C22+ MO diagram. The presence of two unpaired electrons reveals the paramagnetic character of C22+.
∴ Bond order of C22+ = (Nb –Na)/2 = (6 – 4)/2 = 1
MO electronic configuration of C22+: (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px1) (π2py1)
⇒ Paramagnetic
C2– is a negatively charged ion (anion). 1 extra valence electron is gained by a parent C-atom. This extra valence electron singly occupies σ2pz molecular orbital in the Molecular orbital diagram of C2–.
∴ Bond order of C2– = (Nb –Na)/2 = (9 – 4)/2 = 2.5
MO electronic configuration of C2–: (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2) (σ2pz1)
⇒ Paramagnetic
Finally, C22- is formed when 2 extra valence electrons are gained in the 2p AOs, one by each parent C-atom. These two electrons are accommodated as an electron pair in σ2pz in the Molecular orbital diagram of C22-.
The absence of any unpaired electron confirms the diamagnetic nature of C22- unlike C2+, C22+, and C2–.
∴ Bond order of C22- = (Nb –Na)/2 = (10 –4)/2 = 3
MO electronic configuration of C22-: (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2) (σ2pz2).
⇒ Diamagnetic
The bond order also signifies the strength of a bond. Therefore, for the C2 family, the bond strength increases as follows:
C22+ < C2+ < C2 < C2– < C22-
On the contrary, bond order is inversely proportional to bond length. The greater the bond strength, the closer the bonded atoms are to each other, i.e., possessing a shorter bond length.
Therefore, the suspected bond lengths of the C2 family decrease in the order:
C22+ > C2+ > C2 > C2– > C22-
Also read:
- Molecular orbital diagram (MO) for Ne2, Ne2+, Ne22+, and Bond order
- Molecular orbital diagram (MO) for O2+, O2-, O22+, O22-, O2, and Bond order
- Molecular orbital diagram (MO) for He2+, He2, He22+, He22-, He2-, and Bond order
- Molecular orbital diagram (MO) for H2, H2-, H2+, H22-, H22+, and Bond order
- Molecular orbital diagram (MO) for Li2, Li2+, Li2-, Li22-, Li22+, and Bond order
- Molecular orbital diagram (MO) for Be2, Be2+, Be22-, Be2-, Be22+, and Bond order
- Molecular orbital diagram (MO) for B2, B2+, B22-, B2-, B22+, and Bond order
- Molecular orbital diagram (MO) for N2, N2+, N22-, N22+, N2-, and Bond order
- Molecular orbital diagram (MO) for F2, F2+, F2-, F22+, F22-, and Bond order
- Molecular orbital diagram (MO) for NF+, NF, NF-, and Bond order
- Molecular orbital diagram (MO) for NO, NO+, NO-, and Bond order
- H2O Molecular orbital diagram (MO), Bond order
- HF Molecular orbital diagram (MO), Bond order
FAQ
How to draw the Molecular orbital diagram of C2? What is its bond order? |
The molecular orbital (MO) diagram of C2 is shown below. The MO electronic configuration of C2 is (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2). The absence of any unpaired electrons in the above MO diagram reveals that C2 is a diamagnetic molecule. The bond order of C2 is calculated as follows: Bond order = (Nb-Na)/2 = (8-4)/2 = 2 This bond order value implies that C2 is a stable molecule and that there is a double covalent bond between two C-atoms in C2. |
Is C2 a stable molecule as per the molecular orbital theory (MOT)? |
C2 is a stable molecule because it has a positive bond order value. The bond order of C2 is 2, which means there is a double covalent bond between two C-atoms in C2. |
Why does C2– have a stronger bond than C2+? |
The strength of a bond is determined by its bond order value. The higher the bond order, the stronger the bond. The bond order of C2– is 2.5 while that of C2+ is 1.5 which means the carbon-carbon bond in C2– is stronger than that in C2+. |
Among H2, He2+, Li2, Be2, B2, C2, N2, O2– and F2 , the number of diamagnetic species is:
|
Option B gives the correct answer. The MO electronic configurations of the chemical species mentioned above are: H2 = (σ1s2) He2+ = (σ1s2) (σ*1s1) Li2 = (σ1s2) (σ*1s2) (σ2s2) Be2 = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) B2 = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px1) (π2py1) C2 = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2) N2 = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2p2)(σ2pz2) O2– = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (σ2pz2) (π2px2) (π2py2)(π*2px2) (π*2py1) F2 = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (σ2pz2) (π2px2) (π2py2)(π*2px2) (π*2py2) As per the Molecular orbital electronic configurations, the 6 species; H2, Li2, Be2, C2, N2, and F2 are diamagnetic in nature, containing no unpaired electron while the other three, He2+, B2, and O2– are paramagnetic. |
As per their respective Molecular orbital diagrams, what is the correct order of the a) increasing bond energy and b) increasing bond length of C2–, C2, and C2+? |
A high bond order value implies a stronger bond. The higher the bond strength, the more energy is required to break it, in other words, its bond dissociation energy increases. The bond orders of C2–, C2, and C2+ are 2.5, 2, and 1.5 respectively. Therefore, bond energy increases as follows: C2+ < C2 < C2–. In contrast, the higher the bond order, the shorter the bond length. Therefore for the above-mentioned species, bond length increases in the order: C2– < C2 < C2+. |
What is the MO electronic configuration of C2+? Calculate its bond order and comment on its magnetic behavior. |
The Molecular orbital electronic configuration of C2+ is (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py1). Its bond order is calculated as follows: Bond order = (Nb-Na)/2 = (7-4)/2 = 1.5 There is 1 unpaired electron in the π2py MO of C2+. Hence, it exhibits a paramagnetic behavior. |
Which one is paramagnetic out of the three: C2–, C2 or C2+? |
The Molecular orbital electronic configurations of the above-mentioned species are: C2– = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2)(σ2pz1) C2 = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2) C2+ = (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py1) Both C2– and C2+ contain 1 unpaired electron each, therefore both these are paramagnetic while C2 is a diamagnetic specie. |
Arrange the following species in increasing order of bond energy:C2, C2+, C2–, C22+ and C22- |
The higher the bond order, the greater the bond energy. Therefore, the C2 family can be arranged in increasing order of bond energy as follows: C22+ < C2+ < C2 < C2– < C22- |
Summary
- C2 represents a homonuclear diatomic molecule, containing two identical C-atoms.
- The MO electronic configuration of C2 is (σ1s2) (σ*1s2) (σ2s2) (σ*2s2) (π2px2) (π2py2).
- The absence of any unpaired electron in the Molecular orbital diagram of C2 predicts its diamagnetic nature.
- The bond order of C2 is 2 which means there is ideally a double covalent bond between two C-atoms in the C2 molecule.
- C2+, C2–, C22+, and C22- are molecular ions formed by the loss or gain of electrons in the valence shell atomic orbitals of individual C-atoms.
- The bond order follows the ascending pattern: C22+ < C2+ < C2 < C2– < C22- i.e., 1, 1.5, 2, 2.5, and 3 respectively.
- C2+, C2–, and C22+ are paramagnetic while C22- is a diamagnetic specie.
About the author
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