Lutetium (Lu) Bohr Model
- The Bohr Model of Lutetium (Lu) has a nucleus that contains 104 neutrons and 71 protons.
- This nucleus is surrounded by six electron shells.
- The first shell of the Bohr diagram of Lutetium has 2 electrons, the 2nd shell has 8, the 3rd shell has 18, the 4th has 32, the 5th has 9, and the 6th shell has 2 electrons.
|Name||Lutetium Bohr Model|
|Number of neutrons||104|
|Number of protons||71|
|Number of electrons||71|
|Total electron shells||6|
|Electron in the First shell||2|
|Electrons in the Second shell||8|
|Electrons in the Third shell||18|
|Electrons in the Fourth shell||32|
|Electrons in the Fifth shell||9|
|Electrons in the Sixth shell||2|
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