The molar mass and molecular weight of Ammonia (NH3) is 17.0306 g/mol.
The composition of the NH3 formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Hydrogen | H | 1.00797 g/mol | 3 | 3.0239 g/mol | 17.7557% |
| Nitrogen | N | 14.0067 g/mol | 1 | 14.0067 g/mol | 82.2443% |
How to find the molar mass of Ammonia (NH3)?
The molar mass and molecular weight of Ammonia (NH3) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the NH3 compound.
The given compound is NH3. It comprises atoms from 2 different elements i.e., Hydrogen (H) and Nitrogen (N).
Step II: Find the atomic weight of each element in the NH3.
Here is the list of atomic weights for all elements, let’s check the Hydrogen (H) and Nitrogen (N) atom’s atomic weight.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
• The atomic weight of Nitrogen (N) is 14.0067 g/mol.
Step III: Determine the number of atoms of each element present in the NH3 compound.
As per the chemical formula, NH3, It is made up of 3 Hydrogen atoms and 1 Nitrogen atom.
| Element | Number of Atoms |
|---|---|
| H (Hydrogen) | 3 |
| N (Nitrogen) | 1 |
Step IV: Calculate the molar mass of the Ammonia (NH3) compound by applying the formula:
For Ammonia (NH3):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of NH3 = [(1.00797 x 3) + (14.0067 x 1)]
Molar mass of NH3 = 3.0239 + 14.0067 = 17.0306 g/mol
Result: The molecular weight and molar mass of Ammonia (NH3) is 17.0306 g/mol.
FAQs
What is the mass percent composition of Hydrogen (H) in Ammonia (NH3)? |
To find the mass percent of Hydrogen in NH3, follow the steps given below:
∴ Mass of Hydrogen in NH3 = 1.00797 x 3 = 3.0239 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in NH3 = (Mass of Hydrogen in NH3/Molar mass of NH3) × 100% Result: NH3 contains 17.76 % of Hydrogen as per its chemical composition.
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What is the mass percent composition of Nitrogen (N) in Ammonia (NH3)? |
To find the mass percent of Nitrogen in NH3, follow the steps given below:
∴ Mass of Nitrogen in NH3 = 14.0067 x 1 = 14.0067 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Nitrogen in NH3 = (Mass of Nitrogen in NH3/Molar mass of NH3) × 100% Result: NH3 contains 82.24 % of Nitrogen as per its chemical composition.
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What is the atomic percentage composition of elements in Ammonia (NH3)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For NH3: The atomic percentage composition of elements in the compound is: Atomic percentage of Hydrogen (H) in NH3: Atomic percentage of Nitrogen (N) in NH3:
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How many grams of Hydrogen are present in 1 mole of NH3? |
| There are 3 H-atoms in a NH3 molecule. • Atomic weight of a H-atom = 1.00797 g/mol ∴ Total mass of Hydrogen in 1 mole of NH3 = 3 x 1.00797 = 3.02 g. Therefore there are 3.02 grams of Hydrogen in 1 mole of NH3. |
What is the mass of 4 mol of NH3? |
| The molecular mass of NH3 is 17.0306 g/mol. This means 17.0306 grams of NH3 are present per mole. Therefore, we can find the mass of NH3 in 4 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of NH3 = Moles x Molar mass ∴ Mass of NH3 = 4 x 17.0306 = 68.12 g Thus, the mass of 4 mol of NH3 is 68.12 g. |
If you have 4.4141 grams of NH3, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of NH3 = 4.4141/17.0306 = 0.2592 Thus, there are 0.2592 moles of NH3 in its 4.4141 grams. |
What is the mass in kg of 2.84 x 1025 molecules of NH3? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 2.84 x 1025 molecules of NH3 are: ∴ Moles of NH3 = 2.84 x 1025/6.02 x 1023 = 47.2
Now that we have its number of moles, so, we can use the molar mass of NH3 (17.0306 g/mol) to find its mass as shown below. ∴ Mass of NH3 = Moles x Molar mass
∴ Mass of NH3 = 47.2 x 17.0306 = 802.99 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of NH3 = 802.99/1000 = 0.80 kg
The mass of 2.84 x 1025 molecules of NH3 is 0.80 kg.
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What is the molar mass and molecular weight of Ammonia (NH3)? |
NH3 is composed of 3 Hydrogen (H), and 1 Nitrogen (N) atom.
To find the molecular mass of NH3, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For NH3, it’s (3 x 1.0080) + (1 x 14.0067).
Therefore, the molar mass of Ammonia (NH3) is 17.0306 g/mol.
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About the author
Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/