The molar mass and molecular weight of Acetic acid (CH3COOH) is 60.0527 g/mol.
The composition of the CH3COOH formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Hydrogen | H | 1.00797 g/mol | 4 | 4.0319 g/mol | 6.7139% |
| Oxygen | O | 15.9994 g/mol | 2 | 31.9988 g/mol | 53.2845% |
| Carbon | C | 12.011 g/mol | 2 | 24.0220 g/mol | 40.0015% |
How to find the molar mass of Acetic acid (CH3COOH)?
The molar mass and molecular weight of Acetic acid (CH3COOH) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the CH3COOH compound.
The given compound is CH3COOH. It comprises atoms from 3 different elements i.e., Hydrogen (H), Oxygen (O) and Carbon (C).
Step II: Find the atomic weight of each element in the CH3COOH.
Here is the list of atomic weights for all elements, let’s check the Hydrogen (H), Oxygen (O) and Carbon (C) atom’s atomic weight.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
Step III: Determine the number of atoms of each element present in the CH3COOH compound.
As per the chemical formula, CH3COOH, It is made up of 4 Hydrogen atoms, 2 Oxygen atoms and 2 Carbon atoms.
| Element | Number of Atoms |
|---|---|
| H (Hydrogen) | 4 |
| O (Oxygen) | 2 |
| C (Carbon) | 2 |
Step IV: Calculate the molar mass of the Acetic acid (CH3COOH) compound by applying the formula:
For Acetic acid (CH3COOH):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of CH3COOH = [(1.00797 x 4) + (15.9994 x 2) + (12.011 x 2)]
Molar mass of CH3COOH = 4.03188 + 31.9988 + 24.022 = 60.0527 g/mol
Result: The molecular weight and molar mass of Acetic acid (CH3COOH) is 60.0527 g/mol.
FAQs
What is the mass percent composition of Hydrogen (H) in Acetic acid (CH3COOH)? |
To find the mass percent of Hydrogen in CH3COOH, follow the steps given below:
∴ Mass of Hydrogen in CH3COOH = 1.00797 x 4 = 4.0319 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in CH3COOH = (Mass of Hydrogen in CH3COOH/Molar mass of CH3COOH) × 100% Result: CH3COOH contains 6.71 % of Hydrogen as per its chemical composition.
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What is the mass percent composition of Oxygen (O) in Acetic acid (CH3COOH)? |
To find the mass percent of Oxygen in CH3COOH, follow the steps given below:
∴ Mass of Oxygen in CH3COOH = 15.9994 x 2 = 31.9988 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in CH3COOH = (Mass of Oxygen in CH3COOH/Molar mass of CH3COOH) × 100% Result: CH3COOH contains 53.28 % of Oxygen as per its chemical composition.
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What is the mass percent composition of Carbon (C) in Acetic acid (CH3COOH)? |
To find the mass percent of Carbon in CH3COOH, follow the steps given below:
∴ Mass of Carbon in CH3COOH = 12.011 x 2 = 24.0220 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in CH3COOH = (Mass of Carbon in CH3COOH/Molar mass of CH3COOH) × 100% Result: CH3COOH contains 40.00 % of Carbon as per its chemical composition.
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What is the atomic percentage composition of elements in Acetic acid (CH3COOH)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For CH3COOH: The atomic percentage composition of elements in the compound is: Atomic percentage of Hydrogen (H) in CH3COOH: Atomic percentage of Oxygen (O) in CH3COOH: Atomic percentage of Carbon (C) in CH3COOH:
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How many grams of Hydrogen are present in 1 mole of CH3COOH? |
| There are 4 H-atoms in a CH3COOH molecule. • Atomic weight of a H-atom = 1.00797 g/mol ∴ Total mass of Hydrogen in 1 mole of CH3COOH = 4 x 1.00797 = 4.03 g. Therefore there are 4.03 grams of Hydrogen in 1 mole of CH3COOH. |
What is the mass of 8 mol of CH3COOH? |
| The molecular mass of CH3COOH is 60.0527 g/mol. This means 60.0527 grams of CH3COOH are present per mole. Therefore, we can find the mass of CH3COOH in 8 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of CH3COOH = Moles x Molar mass ∴ Mass of CH3COOH = 8 x 60.0527 = 480.42 g Thus, the mass of 8 mol of CH3COOH is 480.42 g. |
If you have 13.0185 grams of CH3COOH, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of CH3COOH = 13.0185/60.0527 = 0.2168 Thus, there are 0.2168 moles of CH3COOH in its 13.0185 grams. |
What is the mass in kg of 10.01 x 1025 molecules of CH3COOH? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 10.01 x 1025 molecules of CH3COOH are: ∴ Moles of CH3COOH = 10.01 x 1025/6.02 x 1023 = 166.3
Now that we have its number of moles, so, we can use the molar mass of CH3COOH (60.0527 g/mol) to find its mass as shown below. ∴ Mass of CH3COOH = Moles x Molar mass
∴ Mass of CH3COOH = 166.3 x 60.0527 = 9984.29 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of CH3COOH = 9984.29/1000 = 9.98 kg
The mass of 10.01 x 1025 molecules of CH3COOH is 9.98 kg.
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What is the molar mass and molecular weight of Acetic acid (CH3COOH)? |
CH3COOH is composed of 4 Hydrogen (H), 2 Oxygen (O), and 2 Carbon (C) atoms.
To find the molecular mass of CH3COOH, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For CH3COOH, it’s (4 x 1.0080) + (2 x 15.9994) + (2 x 12.0110).
Therefore, the molar mass of Acetic acid (CH3COOH) is 60.0527 g/mol.
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About the author
Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/