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Zinc carbonate (ZnCO3) Molar mass and Molecular weight

The molar mass and molecular weight of Zinc carbonate (ZnCO3) is 125.3892 g/mol.

The composition of the ZnCO3 formula is as follows:

Element Symbol Atomic Weight Atoms Total Atomic Weight Mass Percent
Oxygen O 15.9994 g/mol 3 47.9982 g/mol 38.2794%
Carbon C 12.011 g/mol 1 12.0110 g/mol 9.5790%
Zinc Zn 65.38 g/mol 1 65.3800 g/mol 52.1417%

 

The molar mass and molecular weight of Zinc carbonate (ZnCO3)

How to find the molar mass of Zinc carbonate (ZnCO3)?

The molar mass and molecular weight of Zinc carbonate (ZnCO3) can be calculated in 4 steps.

Step I: Identify the different elemental atoms present in the ZnCO3 compound.

The given compound is ZnCO3. It comprises atoms from 3 different elements i.e., Oxygen (O), Carbon (C) and Zinc (Zn).

Step II: Find the atomic weight of each element in the ZnCO3.

Here is the list of atomic weights for all elements, let’s check the Oxygen (O), Carbon (C) and Zinc (Zn) atom’s atomic weight.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
• The atomic weight of Zinc (Zn) is 65.38 g/mol.

atomic weight of each element in ZnCO3

Step III: Determine the number of atoms of each element present in the ZnCO3 compound.

As per the chemical formula, ZnCO3, It is made up of 3 Oxygen atoms, 1 Carbon atom and 1 Zinc atom.

Element Number of Atoms
O (Oxygen) 3
C (Carbon) 1
Zn (Zinc) 1

Step IV: Calculate the molar mass of the Zinc carbonate (ZnCO3) compound by applying the formula:

Formula to calculate Molar mass

For Zinc carbonate (ZnCO3):

Molar mass = Σ [(Atomic weight of Oxygen (O) x Number of O-atoms) + (Atomic weight of Carbon (C) x Number of C-atoms) + (Atomic weight of Zinc (Zn) x Number of Zn-atoms)] in ZnCO3

Substituting into the above formula, the values determined in steps II and III:

Molar mass of ZnCO3 = [(15.9994 x 3) + (12.011 x 1) + (65.38 x 1)]

Molar mass of ZnCO3 = 47.9982 + 12.011 + 65.38 = 125.3892 g/mol

Result: The molecular weight and molar mass of Zinc carbonate (ZnCO3) is 125.3892 g/mol.

FAQs

What is the mass percent composition of Oxygen (O) in Zinc carbonate (ZnCO3)?

To find the mass percent of Oxygen in ZnCO3, follow the steps given below:
  • Determine the atomic weight of Oxygen i.e., 15.9994 g/mol.
  • Find the mass of Oxygen (O) in ZnCO3 by multiplying the atomic weight of an O-atom with the total number of O-atoms in ZnCO3 i.e., 3.

∴ Mass of Oxygen in ZnCO3 = 15.9994 x 3 = 47.9982 g/mol.

Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100

∴ Mass percent of Oxygen in ZnCO3 = (Mass of Oxygen in ZnCO3/Molar mass of ZnCO3) × 100%
∴ Mass percent of Oxygen in ZnCO3 = (47.9982/125.3892) × 100% = 38.28 %

Result: ZnCO3 contains 38.28 % of Oxygen as per its chemical composition.

Mass percent Composition of O in Zinc carbonate (ZnCO3)

 

What is the mass percent composition of Carbon (C) in Zinc carbonate (ZnCO3)?

To find the mass percent of Carbon in ZnCO3, follow the steps given below:
  • Determine the atomic weight of Carbon i.e., 12.011 g/mol.
  • Find the mass of Carbon (C) in ZnCO3 by multiplying the atomic weight of an C-atom with the total number of C-atoms in ZnCO3 i.e., 1.

∴ Mass of Carbon in ZnCO3 = 12.011 x 1 = 12.0110 g/mol.

Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100

∴ Mass percent of Carbon in ZnCO3 = (Mass of Carbon in ZnCO3/Molar mass of ZnCO3) × 100%
∴ Mass percent of Carbon in ZnCO3 = (12.0110/125.3892) × 100% = 9.58 %

Result: ZnCO3 contains 9.58 % of Carbon as per its chemical composition.

Mass percent Composition of C in Zinc carbonate (ZnCO3)

 

What is the mass percent composition of Zinc (Zn) in Zinc carbonate (ZnCO3)?

To find the mass percent of Zinc in ZnCO3, follow the steps given below:
  • Determine the atomic weight of Zinc i.e., 65.38 g/mol.
  • Find the mass of Zinc (Zn) in ZnCO3 by multiplying the atomic weight of an Zn-atom with the total number of Zn-atoms in ZnCO3 i.e., 1.

∴ Mass of Zinc in ZnCO3 = 65.38 x 1 = 65.3800 g/mol.

Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100

∴ Mass percent of Zinc in ZnCO3 = (Mass of Zinc in ZnCO3/Molar mass of ZnCO3) × 100%
∴ Mass percent of Zinc in ZnCO3 = (65.3800/125.3892) × 100% = 52.14 %

Result: ZnCO3 contains 52.14 % of Zinc as per its chemical composition.

Mass percent Composition of Zn in Zinc carbonate (ZnCO3)

 

What is the atomic percentage composition of elements in Zinc carbonate (ZnCO3)?

Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound

For ZnCO3:
• There’s 3 O-atoms, 1 C-atoms, 1 Zn-atoms.
• Total atoms in ZnCO3 = 3 + 1 + 1 = 5

The atomic percentage composition of elements in the compound is:

Atomic percentage of Oxygen (O) in ZnCO3:
= (3/5) * 100
= 60.00%

Atomic percentage of Carbon (C) in ZnCO3:
= (1/5) * 100
= 20.00%

Atomic percentage of Zinc (Zn) in ZnCO3:
= (1/5) * 100
= 20.00%

atomic percent composition in Zinc carbonate (ZnCO3)

 

How many grams of Oxygen are present in 1 mole of ZnCO3?

There are 3 O-atoms in a ZnCO3 molecule.
• Atomic weight of a O-atom = 15.9994 g/mol
∴ Total mass of Oxygen in 1 mole of ZnCO3 = 3 x 15.9994 = 48.00 g.
Therefore there are 48.00 grams of Oxygen in 1 mole of ZnCO3.

 

What is the mass of 5 mol of ZnCO3?

The molecular mass of ZnCO3 is 125.3892 g/mol. This means 125.3892 grams of ZnCO3 are present per mole.
Therefore, we can find the mass of ZnCO3 in 5 moles as follows:
Moles = Mass/Molar Mass
∴ Mass of ZnCO3 = Moles x Molar mass
∴ Mass of ZnCO3 = 5 x 125.3892 = 626.95 g
Thus, the mass of 5 mol of ZnCO3 is 626.95 g.

 

If you have 41.0772 grams of ZnCO3, how many moles do you have?

∴ Moles = Mass/Molar mass
∴ Moles of ZnCO3 = 41.0772/125.3892 = 0.3276
Thus, there are 0.3276 moles of ZnCO3 in its 41.0772 grams.

 

What is the mass in kg of 20.90 x 1025 molecules of ZnCO3?

1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023.
Therefore, the number of moles in 20.90 x 1025 molecules of ZnCO3 are:
∴ Moles of ZnCO3 = 20.90 x 1025/6.02 x 1023 = 347.1

Now that we have its number of moles, so, we can use the molar mass of ZnCO3 (125.3892 g/mol) to find its mass as shown below.

∴ Mass of ZnCO3 = Moles x Molar mass
∴ Mass of ZnCO3 = 347.1 x 125.3892 = 43528.38 g

Converting mass from grams (g) to kilograms (kg) gives us:

∴ Mass of ZnCO3 = 43528.38/1000 = 43.53 kg
The mass of 20.90 x 1025 molecules of ZnCO3 is 43.53 kg.

 

What is the molar mass and molecular weight of Zinc carbonate (ZnCO3)?

ZnCO3 is composed of 3 Oxygen (O), 1 Carbon (C), and 1 Zinc (Zn) atom.
  • The atomic weight of Oxygen is 15.9994 g/mol.
  • The atomic weight of Carbon is 12.011 g/mol.
  • The atomic weight of Zinc is 65.38 g/mol.

To find the molecular mass of ZnCO3, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results.

∴ For ZnCO3, it’s (3 x 15.9994) + (1 x 12.0110) + (1 x 65.3800).

Therefore, the molar mass of Zinc carbonate (ZnCO3) is 125.3892 g/mol.

How to calculate the molar mass of Zinc carbonate (ZnCO3)

 

About the author

Vishal Goyal author of topblogtenz.com

Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/

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