The molar mass and molecular weight of Sodium carbonate (Na2CO3) is 105.9887 g/mol.
The composition of the Na2CO3 formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Oxygen | O | 15.9994 g/mol | 3 | 47.9982 g/mol | 45.2861% |
| Carbon | C | 12.011 g/mol | 1 | 12.0110 g/mol | 11.3323% |
| Sodium | Na | 22.98977 g/mol | 2 | 45.9795 g/mol | 43.3815% |
How to find the molar mass of Sodium carbonate (Na2CO3)?
The molar mass and molecular weight of Sodium carbonate (Na2CO3) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the Na2CO3 compound.
The given compound is Na2CO3. It comprises atoms from 3 different elements i.e., Oxygen (O), Carbon (C) and Sodium (Na).
Step II: Find the atomic weight of each element in the Na2CO3.
Here is the list of atomic weights for all elements, let’s check the Oxygen (O), Carbon (C) and Sodium (Na) atom’s atomic weight.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
• The atomic weight of Sodium (Na) is 22.98977 g/mol.
Step III: Determine the number of atoms of each element present in the Na2CO3 compound.
As per the chemical formula, Na2CO3, It is made up of 3 Oxygen atoms, 1 Carbon atom and 2 Sodium atoms.
| Element | Number of Atoms |
|---|---|
| O (Oxygen) | 3 |
| C (Carbon) | 1 |
| Na (Sodium) | 2 |
Step IV: Calculate the molar mass of the Sodium carbonate (Na2CO3) compound by applying the formula:
For Sodium carbonate (Na2CO3):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of Na2CO3 = [(15.9994 x 3) + (12.011 x 1) + (22.98977 x 2)]
Molar mass of Na2CO3 = 47.9982 + 12.011 + 45.9795 = 105.9887 g/mol
Result: The molecular weight and molar mass of Sodium carbonate (Na2CO3) is 105.9887 g/mol.
FAQs
What is the mass percent composition of Oxygen (O) in Sodium carbonate (Na2CO3)? |
To find the mass percent of Oxygen in Na2CO3, follow the steps given below:
∴ Mass of Oxygen in Na2CO3 = 15.9994 x 3 = 47.9982 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in Na2CO3 = (Mass of Oxygen in Na2CO3/Molar mass of Na2CO3) × 100% Result: Na2CO3 contains 45.29 % of Oxygen as per its chemical composition.
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What is the mass percent composition of Carbon (C) in Sodium carbonate (Na2CO3)? |
To find the mass percent of Carbon in Na2CO3, follow the steps given below:
∴ Mass of Carbon in Na2CO3 = 12.011 x 1 = 12.0110 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in Na2CO3 = (Mass of Carbon in Na2CO3/Molar mass of Na2CO3) × 100% Result: Na2CO3 contains 11.33 % of Carbon as per its chemical composition.
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What is the mass percent composition of Sodium (Na) in Sodium carbonate (Na2CO3)? |
To find the mass percent of Sodium in Na2CO3, follow the steps given below:
∴ Mass of Sodium in Na2CO3 = 22.98977 x 2 = 45.9795 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Sodium in Na2CO3 = (Mass of Sodium in Na2CO3/Molar mass of Na2CO3) × 100% Result: Na2CO3 contains 43.38 % of Sodium as per its chemical composition.
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What is the atomic percentage composition of elements in Sodium carbonate (Na2CO3)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For Na2CO3: The atomic percentage composition of elements in the compound is: Atomic percentage of Oxygen (O) in Na2CO3: Atomic percentage of Carbon (C) in Na2CO3: Atomic percentage of Sodium (Na) in Na2CO3:
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How many grams of Oxygen are present in 1 mole of Na2CO3? |
| There are 3 O-atoms in a Na2CO3 molecule. • Atomic weight of a O-atom = 15.9994 g/mol ∴ Total mass of Oxygen in 1 mole of Na2CO3 = 3 x 15.9994 = 48.00 g. Therefore there are 48.00 grams of Oxygen in 1 mole of Na2CO3. |
What is the mass of 6 mol of Na2CO3? |
| The molecular mass of Na2CO3 is 105.9887 g/mol. This means 105.9887 grams of Na2CO3 are present per mole. Therefore, we can find the mass of Na2CO3 in 6 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of Na2CO3 = Moles x Molar mass ∴ Mass of Na2CO3 = 6 x 105.9887 = 635.93 g Thus, the mass of 6 mol of Na2CO3 is 635.93 g. |
If you have 37.1971 grams of Na2CO3, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of Na2CO3 = 37.1971/105.9887 = 0.3510 Thus, there are 0.3510 moles of Na2CO3 in its 37.1971 grams. |
What is the mass in kg of 17.66 x 1025 molecules of Na2CO3? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 17.66 x 1025 molecules of Na2CO3 are: ∴ Moles of Na2CO3 = 17.66 x 1025/6.02 x 1023 = 293.4
Now that we have its number of moles, so, we can use the molar mass of Na2CO3 (105.9887 g/mol) to find its mass as shown below. ∴ Mass of Na2CO3 = Moles x Molar mass
∴ Mass of Na2CO3 = 293.4 x 105.9887 = 31100.81 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of Na2CO3 = 31100.81/1000 = 31.10 kg
The mass of 17.66 x 1025 molecules of Na2CO3 is 31.10 kg.
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What is the molar mass and molecular weight of Sodium carbonate (Na2CO3)? |
Na2CO3 is composed of 3 Oxygen (O), 1 Carbon (C), and 2 Sodium (Na) atoms.
To find the molecular mass of Na2CO3, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For Na2CO3, it’s (3 x 15.9994) + (1 x 12.0110) + (2 x 22.9898).
Therefore, the molar mass of Sodium carbonate (Na2CO3) is 105.9887 g/mol.
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