The molar mass and molecular weight of Glucose (C6H12O6) is 180.1580 g/mol.
The composition of the C6H12O6 formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Oxygen | O | 15.9994 g/mol | 6 | 95.9964 g/mol | 53.2845% |
| Hydrogen | H | 1.00797 g/mol | 12 | 12.0956 g/mol | 6.7139% |
| Carbon | C | 12.011 g/mol | 6 | 72.0660 g/mol | 40.0015% |
How to find the molar mass of Glucose (C6H12O6)?
The molar mass and molecular weight of Glucose (C6H12O6) can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the C6H12O6 compound.
The given compound is C6H12O6. It comprises atoms from 3 different elements i.e., Oxygen (O), Hydrogen (H) and Carbon (C).
Step II: Find the atomic weight of each element in the C6H12O6.
Here is the list of atomic weights for all elements, let’s check the Oxygen (O), Hydrogen (H) and Carbon (C) atom’s atomic weight.
• The atomic weight of Oxygen (O) is 15.9994 g/mol.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
Step III: Determine the number of atoms of each element present in the C6H12O6 compound.
As per the chemical formula, C6H12O6, It is made up of 6 Oxygen atoms, 12 Hydrogen atoms and 6 Carbon atoms.
| Element | Number of Atoms |
|---|---|
| O (Oxygen) | 6 |
| H (Hydrogen) | 12 |
| C (Carbon) | 6 |
Step IV: Calculate the molar mass of the Glucose (C6H12O6) compound by applying the formula:
For Glucose (C6H12O6):
Substituting into the above formula, the values determined in steps II and III:
Molar mass of C6H12O6 = [(15.9994 x 6) + (1.00797 x 12) + (12.011 x 6)]
Molar mass of C6H12O6 = 95.9964 + 12.0956 + 72.066 = 180.1580 g/mol
Result: The molecular weight and molar mass of Glucose (C6H12O6) is 180.1580 g/mol.
FAQs
What is the mass percent composition of Oxygen (O) in Glucose (C6H12O6)? |
To find the mass percent of Oxygen in C6H12O6, follow the steps given below:
∴ Mass of Oxygen in C6H12O6 = 15.9994 x 6 = 95.9964 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Oxygen in C6H12O6 = (Mass of Oxygen in C6H12O6/Molar mass of C6H12O6) × 100% Result: C6H12O6 contains 53.28 % of Oxygen as per its chemical composition.
|
What is the mass percent composition of Hydrogen (H) in Glucose (C6H12O6)? |
To find the mass percent of Hydrogen in C6H12O6, follow the steps given below:
∴ Mass of Hydrogen in C6H12O6 = 1.00797 x 12 = 12.0956 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in C6H12O6 = (Mass of Hydrogen in C6H12O6/Molar mass of C6H12O6) × 100% Result: C6H12O6 contains 6.71 % of Hydrogen as per its chemical composition.
|
What is the mass percent composition of Carbon (C) in Glucose (C6H12O6)? |
To find the mass percent of Carbon in C6H12O6, follow the steps given below:
∴ Mass of Carbon in C6H12O6 = 12.011 x 6 = 72.0660 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in C6H12O6 = (Mass of Carbon in C6H12O6/Molar mass of C6H12O6) × 100% Result: C6H12O6 contains 40.00 % of Carbon as per its chemical composition.
|
What is the atomic percentage composition of elements in Glucose (C6H12O6)? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For C6H12O6: The atomic percentage composition of elements in the compound is: Atomic percentage of Oxygen (O) in C6H12O6: Atomic percentage of Hydrogen (H) in C6H12O6: Atomic percentage of Carbon (C) in C6H12O6:
|
How many grams of Oxygen are present in 1 mole of C6H12O6? |
| There are 6 O-atoms in a C6H12O6 molecule. • Atomic weight of a O-atom = 15.9994 g/mol ∴ Total mass of Oxygen in 1 mole of C6H12O6 = 6 x 15.9994 = 96.00 g. Therefore there are 96.00 grams of Oxygen in 1 mole of C6H12O6. |
What is the mass of 24 mol of C6H12O6? |
| The molecular mass of C6H12O6 is 180.1580 g/mol. This means 180.1580 grams of C6H12O6 are present per mole. Therefore, we can find the mass of C6H12O6 in 24 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of C6H12O6 = Moles x Molar mass ∴ Mass of C6H12O6 = 24 x 180.1580 = 4323.79 g Thus, the mass of 24 mol of C6H12O6 is 4323.79 g. |
If you have 52.0310 grams of C6H12O6, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of C6H12O6 = 52.0310/180.1580 = 0.2888 Thus, there are 0.2888 moles of C6H12O6 in its 52.0310 grams. |
What is the mass in kg of 30.03 x 1025 molecules of C6H12O6? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 30.03 x 1025 molecules of C6H12O6 are: ∴ Moles of C6H12O6 = 30.03 x 1025/6.02 x 1023 = 498.8
Now that we have its number of moles, so, we can use the molar mass of C6H12O6 (180.1580 g/mol) to find its mass as shown below. ∴ Mass of C6H12O6 = Moles x Molar mass
∴ Mass of C6H12O6 = 498.8 x 180.1580 = 89858.58 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of C6H12O6 = 89858.58/1000 = 89.86 kg
The mass of 30.03 x 1025 molecules of C6H12O6 is 89.86 kg.
|
What is the molar mass and molecular weight of Glucose (C6H12O6)? |
C6H12O6 is composed of 6 Oxygen (O), 12 Hydrogen (H), and 6 Carbon (C) atoms.
To find the molecular mass of C6H12O6, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For C6H12O6, it’s (6 x 15.9994) + (12 x 1.0080) + (6 x 12.0110).
Therefore, the molar mass of Glucose (C6H12O6) is 180.1580 g/mol.
|
About the author
Vishal Goyal is the founder of Topblogtenz, a comprehensive resource for students seeking guidance and support in their chemistry studies. He holds a degree in B.Tech (Chemical Engineering) and has four years of experience as a chemistry tutor. The team at Topblogtenz includes experts like experienced researchers, professors, and educators, with the goal of making complex subjects like chemistry accessible and understandable for all. A passion for sharing knowledge and a love for chemistry and science drives the team behind the website. Let's connect through LinkedIn: https://www.linkedin.com/in/vishal-goyal-2926a122b/