The molar mass and molecular weight of Allyl sulfide (C6H10S) is 114.2057 g/mol.
The composition of the C6H10S formula is as follows:
| Element | Symbol | Atomic Weight | Atoms | Total Atomic Weight | Mass Percent |
|---|---|---|---|---|---|
| Sulfur | S | 32.06 g/mol | 1 | 32.0600 g/mol | 28.0722% |
| Hydrogen | H | 1.00797 g/mol | 10 | 10.0797 g/mol | 8.8259% |
| Carbon | C | 12.011 g/mol | 6 | 72.0660 g/mol | 63.1019% |
How to find the molar mass of C6H10S?
The molar mass and molecular weight of C6H10S can be calculated in 4 steps.
Step I: Identify the different elemental atoms present in the C6H10S compound.
The given compound is C6H10S. It comprises atoms from 3 different elements i.e., Sulfur (S), Hydrogen (H) and Carbon (C).
Step II: Find the atomic weight of each element in the C6H10S.
Here is the list of atomic weight for all elements, let’s check the Sulfur (S), Hydrogen (H) and Carbon (C) atoms atomic weight.
• The atomic weight of Sulfur (S) is 32.06 g/mol.
• The atomic weight of Hydrogen (H) is 1.00797 g/mol.
• The atomic weight of Carbon (C) is 12.011 g/mol.
Step III: Determine the number of atoms of each element present in the C6H10S compound.
As per the chemical formula, C6H10S, It is made up of 1 Sulfur atom, 10 Hydrogen atoms and 6 Carbon atoms.
| Element | Number of Atoms |
|---|---|
| S (Sulfur) | 1 |
| H (Hydrogen) | 10 |
| C (Carbon) | 6 |
Step IV: Calculate the molar mass of the C6H10S compound by applying the formula:
For C6H10S:
Substituting into the above formula, the values determined in steps II and III:
Molar mass of C6H10S = [(32.06 x 1) + (1.00797 x 10) + (12.011 x 6)]
Molar mass of C6H10S = 32.06 + 10.0797 + 72.066 = 114.2057 g/mol
Result: The molecular weight and molar mass of Allyl sulfide (C6H10S) is 114.2057 g/mol.
FAQs
What is the mass percent composition of Sulfur (S) in C6H10S? |
To find the mass percent of Sulfur in C6H10S, follow the steps given below:
∴ Mass of Sulfur in C6H10S = 32.06 x 1 = 32.0600 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Sulfur in C6H10S = (Mass of Sulfur in C6H10S/Molar mass of C6H10S) × 100% Result: C6H10S contains 28.07 % of Sulfur as per its chemical composition.
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What is the mass percent composition of Hydrogen (H) in C6H10S? |
To find the mass percent of Hydrogen in C6H10S, follow the steps given below:
∴ Mass of Hydrogen in C6H10S = 1.00797 x 10 = 10.0797 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Hydrogen in C6H10S = (Mass of Hydrogen in C6H10S/Molar mass of C6H10S) × 100% Result: C6H10S contains 8.83 % of Hydrogen as per its chemical composition.
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What is the mass percent composition of Carbon (C) in C6H10S? |
To find the mass percent of Carbon in C6H10S, follow the steps given below:
∴ Mass of Carbon in C6H10S = 12.011 x 6 = 72.0660 g/mol. Mass Percent Composition (%) Formula = (Mass of Element in the Compound/Molar Mass of the Compound) x 100 ∴ Mass percent of Carbon in C6H10S = (Mass of Carbon in C6H10S/Molar mass of C6H10S) × 100% Result: C6H10S contains 63.10 % of Carbon as per its chemical composition.
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What is atomic percentage composition of elements in C6H10S? |
| Atomic percentage composition formula (%) = Number of atoms of a particular element in a compound/Total number of atoms in that compound
For C6H10S: The atomic percentage composition of elements in the compound is: Atomic percentage of Sulfur (S) in C6H10S: Atomic percentage of Hydrogen (H) in C6H10S: Atomic percentage of Carbon (C) in C6H10S:
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How many grams of Sulfur are present in 1 mole of C6H10S? |
| There are 1 S-atoms in a C6H10S molecule. • Atomic weight of a S-atom = 32.06 g/mol ∴ Total mass of Sulfur in 1 mole of C6H10S = 1 x 32.06 = 32.06 g. Therefore there are 32.06 grams of Sulfur in 1 mole of C6H10S. |
What is the mass of 17 mol of C6H10S? |
| The molecular mass of C6H10S is 114.2057 g/mol. This means 114.2057 grams of C6H10S are present per mole. Therefore, we can find the mass of C6H10S in 17 moles as follows: ∴ Moles = Mass/Molar Mass ∴ Mass of C6H10S = Moles x Molar mass ∴ Mass of C6H10S = 17 x 114.2057 = 1941.50 g Thus, the mass of 17 mol of C6H10S is 1941.50 g. |
If you have 54.9011 grams of C6H10S, how many moles do you have? |
| ∴ Moles = Mass/Molar mass ∴ Moles of C6H10S = 54.9011/114.2057 = 0.4807 Thus, there are 0.4807 moles of C6H10S in its 54.9011 grams. |
What is the mass in kg of 19.03 x 1025 molecules of C6H10S? |
| 1 mole of a substance contains Avogadro number of particles i.e., 6.02 x 1023. Therefore, the number of moles in 19.03 x 1025 molecules of C6H10S are: ∴ Moles of C6H10S = 19.03 x 1025/6.02 x 1023 = 316.2
Now that we have its number of moles so we can use the molar mass of C6H10S (114.2057 g/mol) to find its mass as shown below. ∴ Mass of C6H10S = Moles x Molar mass
∴ Mass of C6H10S = 316.2 x 114.2057 = 36110.03 g
Converting mass from grams (g) to kilograms (kg) gives us: ∴ Mass of C6H10S = 36110.03/1000 = 36.11 kg
The mass of 19.03 x 1025 molecules of C6H10S is 36.11 kg.
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What is the molar mass and molecular weight of Allyl sulfide (C6H10S)? |
C6H10S is composed of 1 Sulfur (S), 10 Hydrogen (H), and 6 Carbon (C) atoms.
To find the molecular mass of C6H10S, one multiplies the atomic weight of each element by its number of atoms in the molecule and then sums the results. ∴ For C6H10S, it’s (1 x 32.0600) + (10 x 1.0080) + (6 x 12.0110).
Therefore, the molar mass of C6H10S is 114.2057 g/mol.
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About the author
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